Behaviour of electron in hydrogen atom when hit by photon

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SUMMARY

The discussion centers on the behavior of an electron in a hydrogen atom when exposed to a photon of energy 11.0 eV. The ground state energy level is -13.6 eV and the first excited state is -3.4 eV, resulting in a transition energy difference of 10.2 eV. When the photon interacts with the electron in the ground state, it does not get excited due to insufficient energy to reach the first excited state. Instead, the photon is reflected, maintaining its energy of 11.0 eV, as the electron cannot absorb the photon energy corresponding to the energy level difference.

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1. Given that the ground energy level of a hydrogen atom is -13.6eV, the 1st excited state -3.4eV. The difference is 10.2eV. Imagine a photon of energy 11.0eV hits the electron at ground state. What will be the final result?

Electron doesn't gets excited, photo bounces off with 11.0eV?
or
Electron goes to 1st excited state, and photon gets red-shifted by 10.2eV.

3. Somehow I think is the latter. There is partial energy loss by the photon, and red-shift happens.
Am I right?
 
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hint: absorption spectrum
 
so,

the answer is the former?

as given a spectrum of EM radiation, the atom will only absorb specific frequency which correspond to the energy difference between the energy levels.

Hence, only the specific frequencies absorbed are missing from the EM spectrum observed.

correct?
 

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