Bernoulli/Continuity, Water flowing at different heights/radii

  • Thread starter Thread starter mknob001
  • Start date Start date
  • Tags Tags
    Water
Click For Summary
SUMMARY

The discussion centers on solving fluid dynamics problems using Bernoulli's equation and the continuity equation for water flowing through a pipe with varying radii and pressures. The participants identify the need to calculate velocities at two points (P1 and P2) and the volume flow rate, given pressures of P1 = 1.95 x 10^5 Pa and P2 = 1.20 x 10^5 Pa, with radii of 3 cm and 1.5 cm respectively. The key challenge is the unknown height difference between the two points, which is essential for applying Bernoulli's equation effectively. The density of water is confirmed as 1000 kg/m³, which is necessary for further calculations.

PREREQUISITES
  • Understanding of Bernoulli's equation
  • Knowledge of the continuity equation (A1V1 = A2V2)
  • Familiarity with fluid dynamics concepts, particularly ideal fluid flow
  • Basic knowledge of pressure and density in fluid mechanics
NEXT STEPS
  • Learn how to apply Bernoulli's equation in scenarios with varying heights and cross-sectional areas
  • Study the implications of pressure differences in fluid flow
  • Explore examples of fluid flow problems involving height differences
  • Investigate the relationship between pressure, velocity, and height in fluid dynamics
USEFUL FOR

Students studying fluid dynamics, engineers working with hydraulic systems, and anyone involved in solving problems related to fluid flow in pipes.

mknob001
Messages
3
Reaction score
0

Homework Statement


Water flows in the pipe below as an ideal fluid where:
P1 = 1.95*10^5 Pa ; Rad @ P1 = 3cm
P2 = 1.20*10^5 Pa ; Rad @ P2 = 1.50 cm
P2 is above P1, but the height difference is UNKNOWN.

Questions:
1. What are the velocities at P1 and P2?
2. Find volume flow rate through the pipe.

I don't have a diagram, but it's pretty simple - known pressures with known radii at UNKNOWN heights.


Homework Equations


P1 = P2 + dgh -- doesn't this assume the areas are the same? (which they aren't)
Bernoulli's.
A1V1 = A2V2


The Attempt at a Solution


1. I used A1V1 = A2V2 to solve the ratio between V1 and V2 (since rad can be used to find A) and solved for v1.

2. I substituted answer for v1 into v1 of bernoulli's equation. This way I can get v2.
BUT, I can't solve Bernoulli's eq. without knowing the heights, h1 and h2.

3. I though P1 - P2 = dgh could work, but I thought this was only for change in height with the same area. Am I wrong?

Help would be much appreciated. I'm so stuck on this whole different areas/heights/pressures thing and my brain is shutting down a bit from the frustration. Haha help?
 
Physics news on Phys.org
Sometimes people us a capital P to represent the sum of the pressure p (lower case) plus ρgz:

P = p + ρgz

Is it possible that that is the case here? Even then, you still need to know the density in order to get the kinetic energy per unit volume.
 
thanks for responding -- sorry that i used dgh, it's just what my teacher uses

Anyway, I don't think so, she definitely means p1 and p2 being the pressure at the bottom and top of the pipe. And we're allowed to use d = 1000 kg/m3 for water so I know the density. I'm just not sure if I can solve for the height (z) with the information given.

I'm thinking that she needs to give us that in order to solve it.

I found a problem that uses the same diagram and all the same information, except this one has a height difference given:
q1376760"]http://www.chegg.com/homework-help/questions-and-answers/water-moves-constricted-pipe-steady-ideal-flow-lower-point-pressure-171-105-pa-pipe-radius-q1376760
[/URL]

I'm guessing this is why I can't solve this, but is there something I'm missing?
 
I agree with you. You need to know the height difference.

Chet
 
Thanks, once I know that this problem will be pretty easy. Thanks!
 

Similar threads

  • · Replies 16 ·
Replies
16
Views
2K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 11 ·
Replies
11
Views
2K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 4 ·
Replies
4
Views
724
  • · Replies 5 ·
Replies
5
Views
4K
  • · Replies 8 ·
Replies
8
Views
3K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 6 ·
Replies
6
Views
3K
Replies
2
Views
2K