Bernoulli equation in a closed loop system

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Homework Help Overview

The discussion revolves around the application of the Bernoulli equation in a closed loop system involving pressure measurements at two points in a pipe. The original poster presents pressure values and assumptions regarding fluid velocity and height differences, seeking clarification on the relationship between pressure and pump head in the context of fluid dynamics.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants explore the implications of pressure differences and the assumption of equal velocities in a constant diameter pipe. Questions arise regarding the interpretation of pressure readings and their relevance to pump operation, as well as the placement of measurement points in relation to the pump.

Discussion Status

The discussion is active, with participants questioning the original poster's assumptions and clarifying the setup of the system. Some guidance has been provided regarding the application of Bernoulli's equations, indicating a productive direction in the exploration of the problem.

Contextual Notes

There is a noted complexity due to the closed loop nature of the system, and participants are considering the implications of differential pressure measurements for pump functionality. The original poster's assumptions about velocity and height differences are also under scrutiny.

icham
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Homework Statement
Bernoulli equation in closed loop system
Relevant Equations
H=p/ρg+V2/2g+z2-p/ρg+V2/2g+z1=hs-hf
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P1 = 5psi P2= 15psi , Z2-Z1 = 0, i assume V2 =V1 because velocity of water is the same everywhere in a pipe of constant diameter
is H friction = H pump = 10psi ?
Please help
 

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Correct. Is that really your question?
 
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how come?
(p2- p1) +H friction = Hp
(15psi-5psi) +10psi = 10psi ?
 
icham said:
how come?
(p2- p1) +H friction = Hp
(15psi-5psi) +10psi = 10psi ?
The thing is in a loop, so if points 1 and 2 are right next to one another, say in the inlet pipe to the pump, P1 = P2
 
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Chestermiller said:
The thing is in a loop, so if points 1 and 2 are right next to one another, say in the inlet pipe to the pump, P1 = P2

but gauges show 15psi and 5psi and it should be a differential pressure for pump to work
 
icham said:
but gauges show 15psi and 5psi and it should be a differential pressure for pump to work
Please specify where you are placing points 1 and 2.
 
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Chestermiller said:
Please specify where you are placing points 1 and 2.

as showns on the circuit, P1 is just after the expansion tank and P2 is after pump let say 10 feet or like half way between pump and the resistance
 
icham said:
as showns on the circuit, P1 is just after the expansion tank and P2 is after pump let say 10 feet or like half way between pump and the resistance
OK. Then there are two Bernoulli equations that you can write: $$\frac{P_2-P_1}{\rho g}=\Delta H_{pump}$$That applies across the top; and $$\frac{P_2-P_1}{\rho g}=\Delta H_{friction}$$That applies across the bottom.
 
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Chestermiller said:
OK. Then there are two Bernoulli equations that you can write: $$\frac{P_2-P_1}{\rho g}=\Delta H_{pump}$$That applies across the top; and $$\frac{P_2-P_1}{\rho g}=\Delta H_{friction}$$That applies across the bottom.

Thank you very much ! you've made my day
 
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