Bernoulli equation application

Click For Summary

Discussion Overview

The discussion revolves around the application of the Bernoulli equation to a scenario involving water levels in an object compared to a current. Participants explore the relationship between fluid velocity, pressure, and water levels, seeking to understand how to apply Bernoulli's principles in this context.

Discussion Character

  • Exploratory
  • Technical explanation
  • Debate/contested

Main Points Raised

  • One participant questions why the water level in the object is above that of the current and seeks to apply the Bernoulli equation to explain this phenomenon.
  • Another participant suggests that the current's pressure and velocity contribute to raising the water level in the object, indicating that these factors are part of Bernoulli's equation.
  • A participant expresses familiarity with the standard form of the Bernoulli equation but seeks clarification on how to determine the necessary velocity for the water level to be elevated above the normal level.
  • There is a suggestion that any velocity will cause the water level in the pipe to rise, prompting a request for further elaboration on this point.

Areas of Agreement / Disagreement

Participants do not reach a consensus on the specific application of the Bernoulli equation or the conditions under which the water level rises. Multiple viewpoints regarding the relationship between velocity and water level remain present.

Contextual Notes

There are unresolved assumptions regarding the specific conditions under which the Bernoulli equation is applied, including the definitions of pressure and velocity in this scenario.

Chemist@
Messages
115
Reaction score
1
Why is the water level in the object above the water level of the current? How to apply Bernoulli equation in this case?
 

Attachments

  • untitled.GIF
    untitled.GIF
    1.6 KB · Views: 549
Physics news on Phys.org
The water level in the object is above the water level in the current because the current is supplying enough pressure to push the water that high. The current has a velocity, and you can probably imagine that faster velocity entails a higher water level in the object. There is also a distance involved, which is the height of the fluid in the object. Velocity, pressure, and distance are all part of Bernoulli's equation.
 
I know all that, but how would the equation look like in this case.
 
It's the standard/most common form of the equation. Have you looked it up?
 
I know the standard form. What must be the velocity so that the water level in the object is above the normal level? Is it: V>sqrt(2pa/ro)
 
For your sketch, any velocity will cause the water level in the pipe to rise.
 
Could you please elaborate why?
 

Similar threads

Undergrad Help Regarding Application of Bernoulli in a Boundary Layer
  • · Replies 1 ·
Replies
1
Views
2K
Undergrad Fluid dynamics: drag coefficient and pressure at the stagnation point.
  • · Replies 1 ·
Replies
1
Views
2K
Undergrad Why Does Differential Pressure Vary As The Square Of The Flow?
  • · Replies 8 ·
Replies
8
Views
1K
Undergrad Exit velocity through a nozzle: Bernoulli vs. Experience
  • · Replies 7 ·
Replies
7
Views
4K
Undergrad Bernoulli's equation and the work energy theorem
  • · Replies 21 ·
Replies
21
Views
3K
Graduate Bernoulli's equation, different streamlines, and wings
  • · Replies 4 ·
Replies
4
Views
2K
Undergrad Demystifying the Often Misunderstood Bernoulli's Equation - Comments
  • · Replies 19 ·
Replies
19
Views
3K
Graduate Bernoulli to explain Magnus Effect
  • · Replies 2 ·
Replies
2
Views
3K
Graduate Why Does Hagen-Poiseuille Predict Higher Exit Velocity Than Bernoulli?
  • · Replies 11 ·
Replies
11
Views
3K
Undergrad Is Bernoulli's Equation related to the Conservation of Mechanical Energy?
  • · Replies 2 ·
Replies
2
Views
1K