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Bernoulli equation application

  1. Nov 15, 2014 #1
    Why is the water level in the object above the water level of the current? How to apply Bernoulli equation in this case?
     

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  3. Nov 15, 2014 #2
    The water level in the object is above the water level in the current because the current is supplying enough pressure to push the water that high. The current has a velocity, and you can probably imagine that faster velocity entails a higher water level in the object. There is also a distance involved, which is the height of the fluid in the object. Velocity, pressure, and distance are all part of Bernoulli's equation.
     
  4. Nov 15, 2014 #3
    I know all that, but how would the equation look like in this case.
     
  5. Nov 15, 2014 #4

    russ_watters

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    Staff: Mentor

    It's the standard/most common form of the equation. Have you looked it up?
     
  6. Nov 15, 2014 #5
    I know the standard form. What must be the velocity so that the water level in the object is above the normal level? Is it: V>sqrt(2pa/ro)
     
  7. Nov 15, 2014 #6

    russ_watters

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    Staff: Mentor

    For your sketch, any velocity will cause the water level in the pipe to rise.
     
  8. Nov 15, 2014 #7
    Could you please elaborate why?
     
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