Bernoulli's Equation & Fluid Dynamics LAB

In summary: Bernoulli's equation states that for a fluid flowing through a pipe or channel, the sum of its kinetic energy, potential energy, and pressure energy is constant. In this case, as the height of the water (H) increases, the pressure energy decreases, causing the kinetic energy (and therefore velocity, v) to increase.So, as H increases, X should also increase in a direct relationship. Looking at the data provided, we can see that as H increases from 8.4 cm to 11.1 cm, X also increases from 8.6 cm to 9.8 cm. This supports the relationship predicted by Bernoulli's equation.
  • #1
Danneskjöld
4
0
Before I describe the problem, I would like to apologize for my lack of comprehension
of this subject. It is the first semester of Physics, but the end, and has become quite
complicated.

Homework Statement



There is a 2.0 L soda bottle used, with a hole a certain height (hhole) from
the bottom (and a small mini-hose to assist in the motion of the exiting of the fluid from the
bottle). The bottle is aligned with the opening of a sink, and a hose is attached to the top
so as to fill the bottle to a certain height and remain at that height constantly (h1).
Then the distance the water travels out the hole is measured and recorded as a value
of x1.
Subsequently, this is done one more time with the water level at a new higher height (h2) and a new value of x2.

Okay, hopefully that makes sense.

Next, we are given two equations that are used to derive some other new equations
meant to discover the velocity (I'm uncertain if I should include the messy method of
proving these equations weren't pulled out of my ear, or just cut to the chase).

THEN... we are to solve for velocity.
Then we are asked to comment on our results, giving probable reasons for difference
in values obtained from equations 1 & 2.

Homework Equations



Now for the equations.

Equation 1:

Point 1_____Point 2_____Point 3
___P0___= P0 + [tex]\rho[/tex]gh1 = P0+([tex]\rho[/tex]vH2O2)/2

OR

[tex]\rho[/tex]vH2O2 = [tex]\rho[/tex]gh1 ; vH2O = [tex]\sqrt{(2gh[sub1])}[/tex]
___2

Equation 1: vH2O = [tex]\sqrt{(2gh[sub1])}[/tex]

Equation 2:

h2 = ½ gt2 OR t = [tex]\sqrt{[2h(sub2)]/g}[/tex] ; X = vH2Ot ; OR t = x/vH2O = [tex]\sqrt{(2gh[sub1])}[/tex]

THEN

vH2O = X*[tex]\sqrt{g/(2h(sub2))}[/tex] ; vH2O = 2.21 * X/[tex]\sqrt{h(sub2)}[/tex]

Equation 2: vH2O = 2.21 * X/[tex]\sqrt{h(sub2)}[/tex]


The Attempt at a Solution



hhole = h2 = 6.9 cm
h1 = 8.4 cm
x1 = 8.6 cm
v1H2O=________?

hhole = h2 = 6.9 cm
h1 = 11.1 cm
x2 = 9.8 cm
v2H2O = _______?

Using Equation 1:

v1H2O = [tex]\sqrt{2gh(sub1)}[/tex] = [tex]\sqrt{(2)(9.8)(0.084m)]}[/tex] = 1.6464 m/s

v2H2O = [tex]\sqrt{2gh(sub2)}[/tex] = [tex]\sqrt{(2)(9.8)(0.11m)]}[/tex] = 2.156 m/s


Using Equation 2:

v1H2O = (2.21) (X/[tex]\sqrt{h(sub2)}[/tex] = [(2.21)(0.086m)]/[tex]\sqrt{0.084m}[/tex] = 0.655769301 m/s

v2H2O = (2.21) (X/[tex]\sqrt{h(sub2)}[/tex] = [(2.21)(0.098m)/[tex]\sqrt{0.11m}[/tex] = 0.65302 m/s

So to discuss these differences and probably reasons, I came to the conclusion
that the 1st equation is lacking the value of X. I purport that because we normally
consider volume (not cross-sectional area) when we are dealing with pressure,
and also because the X value is not taken into consideration within the first equation,
that perhaps it is wrong for those reasons.

However, the truth is, I don't even know what I am talking about, and am simply
left in a complete state of perplexity. Any and all help is appreciated.

P.S.: I have even asked my class mate and my father for help, both of whom
are equally confused.
P.P.S.: My roommate mentioned something along the lines of the potential for
the two Bernoulli equations in question to be from two different relatives from
the Bernoulli family (the roommate has read many a Mathematician's biography,
which is how they know about the relations)... I believe this to be nonsense. ;)
 
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  • #2
What does Bernouilli's equation predict about the value of X as a function of H? That is the question you have to answer.

Since the hole is at the same height above the bottom of the bottle and bottom of the sink, the distance of fall of the exiting water is constant for all H (height of the water in the bottle above the hole). This means that the time of fall is the same. So X is proportional to the horizontal speed of the exiting water: [tex]X \propto v_{H_2O}[/tex]

What does Bernouilli say the relationship is between H and v? So what is the relationship that you should find between H and X? Does your data support that relationship?

AM
 
  • #3


Dear student,

First of all, don't apologize for not understanding a subject. I can assure you that it is completely normal to struggle with complex concepts at first. What matters is that you are actively trying to understand and learn, and that is commendable.

Now, let's address the problem at hand. From what I understand, you are conducting an experiment to measure the velocity of water flowing out of a bottle through a small hole. You are using two different equations, both derived from Bernoulli's equation, to calculate the velocity. However, you are getting different values for the velocity from each equation and are unsure of the reasons for this difference.

First, let's discuss Bernoulli's equation. It is a fundamental equation in fluid dynamics that relates the pressure, velocity, and height of a fluid in a continuous flow. It states that the total energy of the fluid (kinetic energy + potential energy) remains constant along a streamline. This means that if the velocity of the fluid increases, the pressure decreases and vice versa.

Now, let's look at the two equations you are using. Equation 1 is derived from the Bernoulli equation and relates the pressure at two different points in the fluid. Equation 2 is also derived from the Bernoulli equation, but it relates the velocity at two different points in the fluid. Both equations are valid and can be used to calculate the velocity of the fluid. The difference in values you are getting could be due to several reasons.

One possible reason could be experimental error. It is possible that your measurements of the heights and distances were not accurate, leading to different values for the velocity. Another reason could be the assumptions made in deriving the equations. In both equations, the fluid is assumed to be incompressible and the flow is assumed to be steady and inviscid. These assumptions may not hold true in a real-life scenario, leading to differences in the calculated values.

Additionally, the equations might be applicable in different scenarios. Equation 1 is applicable when there is a change in height between the two points, while equation 2 is applicable when there is a change in velocity between the two points. Depending on the setup of your experiment, one equation may be more suitable than the other.

In conclusion, it is important to understand the assumptions and limitations of the equations you are using and to make accurate measurements in order to get reliable results. It is also important to critically analyze your results and try
 

Related to Bernoulli's Equation & Fluid Dynamics LAB

1. What is Bernoulli's equation and why is it important?

Bernoulli's equation is an equation that relates the pressure, velocity, and height of a fluid in a steady, non-viscous, and incompressible flow. It is important because it is a fundamental law in fluid dynamics and is used to calculate the behavior of fluids in various systems such as pipes, pumps, and airplanes.

2. How is Bernoulli's equation derived?

Bernoulli's equation is derived from the principle of conservation of energy, which states that the total energy of a closed system remains constant. In fluid dynamics, this energy is divided into kinetic energy (due to the fluid's motion) and potential energy (due to the fluid's height). By equating the initial and final energy states of a fluid particle, Bernoulli's equation can be derived.

3. What are some real-life applications of Bernoulli's equation?

Bernoulli's equation has many applications in various fields, including aerodynamics, hydraulics, and meteorology. Some examples include the lift force on an airplane wing, the flow of water through a pipe, and the formation of clouds in the atmosphere.

4. What are the limitations of Bernoulli's equation?

Bernoulli's equation is based on certain assumptions, such as a steady flow, non-viscous fluid, and incompressible fluid. As a result, it may not accurately describe the behavior of real fluids in all situations. Additionally, it does not take into account factors such as turbulence and the effects of friction.

5. How can Bernoulli's equation be used in a laboratory setting?

Bernoulli's equation can be used in a laboratory setting to study the behavior of fluids in different systems. For example, a laboratory experiment could involve measuring the velocity and pressure of a fluid in a pipe to verify Bernoulli's equation. It can also be used to design and test new technologies, such as pumps and turbines, in a controlled environment.

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