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Bernoulli's principle- fluids ?

  1. Nov 18, 2009 #1
    bernoulli's principle- fluids....?

    1. The problem statement, all variables and given/known data

    http://img30.imageshack.us/img30/4119/45086777.jpg [Broken]

    2. Relevant equations

    A1V1=A2V2
    P2+1/2pv1^2 = p1+1/2pv2^2
    P+1/2mv^2 + pgy = constant

    3. The attempt at a solution

    V2=A1*V1/A2
    1/2*p*A1^2*V1^2*p*g*h/A2^2=1/2pv1^2
    2*g*h*A1^2V1^2/ A2^2=V1^2
    V1=A1*V1gh/A2


    and im stuck.... i end up canceling the V1 >:(
     
    Last edited by a moderator: May 4, 2017
  2. jcsd
  3. Nov 18, 2009 #2
    Re: bernoulli's principle- fluids....?

    GOOOOD!!!
    i've tried like 10 different things and i cant get it..
     
  4. Nov 19, 2009 #3

    ehild

    User Avatar
    Homework Helper
    Gold Member

    Re: bernoulli's principle- fluids....?

    Do you think this equation correct? "P2+1/2pv1^2 = p1+1/2pv2^2"

    ehild
     
  5. Nov 19, 2009 #4

    minger

    User Avatar
    Science Advisor

    Re: bernoulli's principle- fluids....?

    Write out your full Bernoulli's equation:
    [tex]
    P + \frac{\rho V^2}{2} + \rho g z = c
    [/tex]
    The pressure values are both places are ambient so they cancel. You have the change in distance z2 - z1, so the only thing left is to find the velocity. Unfortunately, you don't have this.

    So, it will be useful to write our your velocity term as a function of mass flow and area. You know that mass flow is equal, so you will eventually be left with simply area.
     
  6. Nov 19, 2009 #5
    Re: bernoulli's principle- fluids....?

    i got it!!
    thanks !!!!!!!! :D
     
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