Bernoulli's principle- fluids ?

1. Nov 18, 2009

A_Munk3y

bernoulli's principle- fluids....?

1. The problem statement, all variables and given/known data

http://img30.imageshack.us/img30/4119/45086777.jpg [Broken]

2. Relevant equations

A1V1=A2V2
P2+1/2pv1^2 = p1+1/2pv2^2
P+1/2mv^2 + pgy = constant

3. The attempt at a solution

V2=A1*V1/A2
1/2*p*A1^2*V1^2*p*g*h/A2^2=1/2pv1^2
2*g*h*A1^2V1^2/ A2^2=V1^2
V1=A1*V1gh/A2

and im stuck.... i end up canceling the V1 >:(

Last edited by a moderator: May 4, 2017
2. Nov 18, 2009

A_Munk3y

Re: bernoulli's principle- fluids....?

GOOOOD!!!
i've tried like 10 different things and i cant get it..

3. Nov 19, 2009

ehild

Re: bernoulli's principle- fluids....?

Do you think this equation correct? "P2+1/2pv1^2 = p1+1/2pv2^2"

ehild

4. Nov 19, 2009

minger

Re: bernoulli's principle- fluids....?

Write out your full Bernoulli's equation:
$$P + \frac{\rho V^2}{2} + \rho g z = c$$
The pressure values are both places are ambient so they cancel. You have the change in distance z2 - z1, so the only thing left is to find the velocity. Unfortunately, you don't have this.

So, it will be useful to write our your velocity term as a function of mass flow and area. You know that mass flow is equal, so you will eventually be left with simply area.

5. Nov 19, 2009

A_Munk3y

Re: bernoulli's principle- fluids....?

i got it!!
thanks !!!!!!!! :D