Between which layers first stimulation energy

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SUMMARY

The discussion centers on the excitation energy of mercury as demonstrated in the Frank-Hertz experiment, which identifies that 4.86 eV is required for the first excitation energy. This energy corresponds to the 2.537 Angstrom line in the mercury spectrum, specifically transitioning from the S10 to the P31 energy levels. Understanding this phenomenon necessitates applying selection rules to the atomic structure of mercury.

PREREQUISITES
  • Understanding of the Frank-Hertz experiment
  • Knowledge of excitation energy and electron transitions
  • Familiarity with atomic orbitals (K, L, M layers)
  • Basic grasp of selection rules in quantum mechanics
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  • Research the Frank-Hertz experiment methodology and results
  • Study the concept of excitation energy in atomic physics
  • Examine the mercury emission spectrum and its significance
  • Learn about selection rules and their application in quantum mechanics
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Students and researchers in atomic physics, educators teaching quantum mechanics, and anyone interested in the behavior of electrons in atomic structures.

Volcano
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I am trying to understand excitement energy. Frank-Hertz experiment says mercury need 4,86eV for 1st excitement energy but i wonder between which orbitals, layers(K,L,M,...) etc.
 
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Volcano said:
I am trying to understand excitement energy. Frank-Hertz experiment says mercury need 4,86eV for 1st excitement energy but i wonder between which orbitals, layers(K,L,M,...) etc.

In the mercury spectrum, this energy corresponds to the 2.537 Ang line. So, by looking at the spectrum in the Frank Hertz Nobel Lecture (Fig3,p23) you will find the energy levels : [tex]S^{1}_{0}[/tex] to [tex]P^{3}_{1}[/tex]. To understand this, you need to apply the selection rules onto the atomic structure of mercury.

marlon
 
This is great. Thank you very much.
 

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