Bilinear maps: showing nondegenerate in second variable

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The discussion revolves around proving that the bilinear map B: V* x V -> F is non-degenerate in the second variable, meaning that if B(alpha, v) = 0 for all alpha in V*, then v must be zero. Participants express uncertainty about how to demonstrate this property and whether knowledge of symmetry or skew-symmetry is relevant. There is also a mention of confusion regarding the definitions of linear functionals and their evaluations. The thread highlights the challenge of understanding the proof without access to provided answers from the university.
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Homework Statement



Let V be a n-dimensional vector space.
Let B: V* x V -> F (field) be the bilinear map defined by B(alpha,v) = alpha(v). Show that B in nondegenerate in the second variable. (4 marks)

Homework Equations



I know that B is non-degenerate in the second variable if; B(alpha,v)=0 for every alpha a member of V* which implies that v=0.

The Attempt at a Solution



My attempt was writing out the definition I know (applying it to the variables given). I do not know how to show that it is true for the bilinear map given.

The other thing I know, but not sure if it helps or not, is that if B is symmetric/skew then we can define the radical so that B is non-degenerate on each variable iff radB={0}. But I'm not sure if I need this or not.

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I am currently working through some of the past papers I did for my second year units at university, trying to understand the things I couldn't do at the time ready for my third year units. However obviously the university hasn't supplied us with answers yet so I cannot check what I am doing is correct or not. Thank you for your help!

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MimuiSnoopy said:

Homework Statement



Let V be a n-dimensional vector space.
Let B: V* x V -> F (field) be the bilinear map defined by B(alpha,v) = alpha(v). Show that B in nondegenerate in the second variable. (4 marks)

Homework Equations



I know that B is non-degenerate in the second variable if; B(alpha,v)=0 for every alpha a member of V* which implies that v=0.

The Attempt at a Solution



My attempt was writing out the definition I know (applying it to the variables given). I do not know how to show that it is true for the bilinear map given.

The other thing I know, but not sure if it helps or not, is that if B is symmetric/skew then we can define the radical so that B is non-degenerate on each variable iff radB={0}. But I'm not sure if I need this or not.

----

I am currently working through some of the past papers I did for my second year units at university, trying to understand the things I couldn't do at the time ready for my third year units. However obviously the university hasn't supplied us with answers yet so I cannot check what I am doing is correct or not. Thank you for your help!

----

I guess I am confused about the question.
A non zero linear functional must by definition evaluate to a non-zero number for some vector. No?
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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