Bilinear maps: showing nondegenerate in second variable

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SUMMARY

The forum discussion centers on demonstrating that the bilinear map B: V* x V -> F, defined by B(alpha,v) = alpha(v), is non-degenerate in the second variable. It is established that B is non-degenerate if B(alpha,v) = 0 for every alpha in V* implies that v must equal 0. The discussion also touches on the relationship between symmetry, skewness, and the radical of B, noting that B is non-degenerate on each variable if and only if radB = {0}. Participants express confusion regarding the application of these concepts in their homework context.

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Homework Statement



Let V be a n-dimensional vector space.
Let B: V* x V -> F (field) be the bilinear map defined by B(alpha,v) = alpha(v). Show that B in nondegenerate in the second variable. (4 marks)

Homework Equations



I know that B is non-degenerate in the second variable if; B(alpha,v)=0 for every alpha a member of V* which implies that v=0.

The Attempt at a Solution



My attempt was writing out the definition I know (applying it to the variables given). I do not know how to show that it is true for the bilinear map given.

The other thing I know, but not sure if it helps or not, is that if B is symmetric/skew then we can define the radical so that B is non-degenerate on each variable iff radB={0}. But I'm not sure if I need this or not.

----

I am currently working through some of the past papers I did for my second year units at university, trying to understand the things I couldn't do at the time ready for my third year units. However obviously the university hasn't supplied us with answers yet so I cannot check what I am doing is correct or not. Thank you for your help!

----
 
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MimuiSnoopy said:

Homework Statement



Let V be a n-dimensional vector space.
Let B: V* x V -> F (field) be the bilinear map defined by B(alpha,v) = alpha(v). Show that B in nondegenerate in the second variable. (4 marks)

Homework Equations



I know that B is non-degenerate in the second variable if; B(alpha,v)=0 for every alpha a member of V* which implies that v=0.

The Attempt at a Solution



My attempt was writing out the definition I know (applying it to the variables given). I do not know how to show that it is true for the bilinear map given.

The other thing I know, but not sure if it helps or not, is that if B is symmetric/skew then we can define the radical so that B is non-degenerate on each variable iff radB={0}. But I'm not sure if I need this or not.

----

I am currently working through some of the past papers I did for my second year units at university, trying to understand the things I couldn't do at the time ready for my third year units. However obviously the university hasn't supplied us with answers yet so I cannot check what I am doing is correct or not. Thank you for your help!

----

I guess I am confused about the question.
A non zero linear functional must by definition evaluate to a non-zero number for some vector. No?
 

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