Binary System in circular orbit: Separation distance between stars

Click For Summary
The discussion centers on calculating the orbital period of a binary star system with a separation distance of 14.3 parsecs. The Doppler shift indicates a velocity of 23.4 km/s for both stars, as they share the same mass. Based on a separation of 0.04 nm every 26 years, the estimated full orbital period is 52 years. The inclination of the orbital plane is noted to be 90 degrees, suggesting an edge-on view of the system. This information is crucial for completing the calculations related to the binary system's dynamics.
Thomas Smith
Messages
12
Reaction score
0
Homework Statement
The binary system has a parallax of 0.07 arc seconds. This system consists of two identical stars in circular orbits.

An absorption line at a wavelength of 512nm is seen in the spectra of both stars. This line is split into two components by the orbital motion and has a maximum separation of 0.04nm, which occurs every 26 years.

What's the separation distance between both stars?
Relevant Equations
Distance to Star System from parallax d=1/p

Doppler Shift Δλ = λ - λ_0

Radical Velocity v_r=Δλ/λ_0 c
Distance is d=1/0.07 = 14.3 parsecs

The Doppler shift of one star is, Δλ = 512 - 512.04 = -0.04

So the radical of the velocity of the star is = (-0.04/512) x (3.00 x 10^5 km/s) = 23.4km/s which is the same for both stars because they have the same mass.
This is as far as I've got.
 
Last edited:
Physics news on Phys.org
From the information provided, can you determine the orbital period of the binary system?
 
jbriggs444 said:
From the information provided, can you determine the orbital period of the binary system?
Well considering the separation of 0.04nm every 26 years, I believe the full orbit period is 52 years.
 
If you make an assumption about orientation, you have tangential velocity and period...
 
jbriggs444 said:
If you make an assumption about orientation, you have tangential velocity and period...
Ah sorry, i missed out the inclination. It says the orbital plane is inclined to the plane of the sky by 90 degrees
 
Thomas Smith said:
Ah sorry, i missed out the inclination. It says the orbital plane is inclined to the plane of the sky by 90 degrees
That was the assumption I'd needed for the problem to make sense. So we are looking at the binary system, "edge on". Does that give you everything you need to finish the exercise?
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

Similar threads

  • · Replies 6 ·
Replies
6
Views
1K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 2 ·
Replies
2
Views
6K
Replies
10
Views
3K
  • · Replies 2 ·
Replies
2
Views
2K
Replies
5
Views
2K
Replies
1
Views
2K
Replies
2
Views
4K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 12 ·
Replies
12
Views
5K