Binding energy of a nitrogen nucleus

Join the discussion
Ask a follow-up here, or get your own question answered by working scientists, mathematicians and engineers — people, not an autocomplete.
Real named experts · corrections over time · the nuance an AI answer skips
2 replies · 3K views
cosmictide
Messages
37
Reaction score
0

Homework Statement



Hi guys, any help here would be greatly appreciated.

I'm told that a carbon-12 atom fuses with a hydrogen nucleus with the atomic mass of 1 to form a nucleus of nitrogen releasing 1.95 MeV as a result.

I'm asked to write an equation of the reaction and work out the binding energy of the nitrogen nucleus if the binding energy for the hydrogen is 0 MeV and the binding energy for the carbon-12 is -92.2MeV.

The equation I managed to get is 12C + 1H = 13N + 1.95 MeV. Is this correct? Also how do I work out the binding energy of the nitrogen nucleus? I thought it might be -94.15 MeV but that seems too simple. Any help would be hugely appreciated.

Thanks in advance. :smile:
 
Physics news on Phys.org
cosmictide said:

Homework Statement



Hi guys, any help here would be greatly appreciated.

I'm told that a carbon-12 atom fuses with a hydrogen nucleus with the atomic mass of 1 to form a nucleus of nitrogen releasing 1.95 MeV as a result.

I'm asked to write an equation of the reaction and work out the binding energy of the nitrogen nucleus if the binding energy for the hydrogen is 0 MeV and the binding energy for the carbon-12 is -92.2MeV.

The equation I managed to get is 12C + 1H = 13N + 1.95 MeV. Is this correct? Also how do I work out the binding energy of the nitrogen nucleus? I thought it might be -94.15 MeV but that seems too simple. Any help would be hugely appreciated.

Thanks in advance. :smile:

Not familiar with how such equations are written, but I would have expected to see more detail, like counts of nucleons. On the net I see formalisms like [atomic mass/atomic number]element symbol, e.g. [12/6]C.
For the energy, I would have guessed (by conservation) the simple and obvious relationship between the initial and final binding energy totals and the energy released that you appear to have used.
 
  • Like
Likes   Reactions: 1 person
haruspex said:
Not familiar with how such equations are written, but I would have expected to see more detail, like counts of nucleons. On the net I see formalisms like [atomic mass/atomic number]element symbol, e.g. [12/6]C.
For the energy, I would have guessed (by conservation) the simple and obvious relationship between the initial and final binding energy totals and the energy released that you appear to have used.

Thanks for your reply. I think I'll take your advice and rewrite the formula with the atomic mass and number included.