Calculating Binding Energy for C13 Neutron Removal

In summary: What's the difference between total binding energy then since it is also the energy required to disassemble the nucleusStill not...completely...clear to me, per nucleon as in we remove the nucleons one by one and add up all the energies required in each step? What's the difference between total binding energy then since it is also the energy required to disassemble the nucleusBinding energy is the energy required to separate all the nucleons (=Δmc^2).Total binding energy is the total amount of energy required. The binding energy per nucleon is the total divided
  • #1
Krushnaraj Pandya
Gold Member
697
73

Homework Statement


My textbook says the binding energy per nucleon is the energy needed to remove one nucleon from the nucleus, In a subsequent numerical which is as follows "The binding energy per nucleon for C12 is 7.68 MeV and that for C13 is 7.47 MeV. Calculate the energy required to remove a neutron from C13".The solution given is-"13 X 7.47 - 12 X 7.68 = 4.95 MeV".

Homework Equations

The Attempt at a Solution


According to the definition provided of binding energy per nucleon the answer should be just 7.47 MeV, instead they calculated the Q value- Why did they do that and what blunder am I making? I'd really appreciate your help, thank you.
 
Physics news on Phys.org
  • #2
Krushnaraj Pandya said:
My textbook says the binding energy per nucleon is the energy needed to remove one nucleon from the nucleus,

Yes, there does appear to be a discrepancy at first glance, doesn't there? Unfortunately you're the victim of a bad definition. A better definition would be that binding energy is the energy required to completely 'disassemble' the nucleus. So it's the energy required to separate all the nucleons, not just remove one.
 
  • #3
Drakkith said:
Yes, there does appear to be a discrepancy at first glance, doesn't there? Unfortunately you're the victim of a bad definition. A better definition would be that binding energy is the energy required to completely 'disassemble' the nucleus. So it's the energy required to separate all the nucleons, not just remove one.
That was the definition given for binding energy.
Note that the definition I refer to is for the binding energy per nucleon. I know Binding energy is the energy required to separate all the nucleons (=Δmc^2),
what then is the correct definition of Binding energy per nucleon?
 
  • #4
Krushnaraj Pandya said:
That was the definition given for binding energy.
Note that the definition I refer to is for the binding energy per nucleon. I know Binding energy is the energy required to separate all the nucleons (=Δmc^2),
what then is the correct definition of Binding energy per nucleon?

The energy per nucleon required to completely disassemble the nucleus.
 
  • #5
Drakkith said:
The energy per nucleon required to completely disassemble the nucleus.
Still not clear to me, per nucleon as in we remove the nucleons one by one and add up all the energies required in each step? What's the difference between total binding energy then since it is also the energy required to disassemble the nucleus
 
  • #6
Krushnaraj Pandya said:
Still not clear to me, per nucleon as in we remove the nucleons one by one and add up all the energies required in each step? What's the difference between total binding energy then since it is also the energy required to disassemble the nucleus

It doesn't matter if you remove the nucleons one at a time or all at once. The total energy remains the same. The difference between the total binding energy and the binding energy per nucleon is right in their names. Total binding energy is the total amount of energy required. The binding energy per nucleon is the total divided by the number of nucleons.

Note that the actual energy you would spend to remove successive nucleons, one at a time, changes as you remove more and more nucleons. Consider lithium-6, with a binding energy of around 5.3 MeV per nucleon. If you remove a proton and a neutron you get helium-4, with a binding energy of around 7.075 MeV per nucleon. Thus the energy spent to remove successive nucleons must change, otherwise every element would have identical binding energy per nucleon. That is, if it took 5.3 MeV to remove every single nucleon, one at a time, from a nucleus of lithium-6, then after removing a proton and a neutron our binding energy per nucleon should still be 5.3 MeV. But it's not. It has risen to around 7 MeV. That means it took less than 5.3 MeV to remove that first nucleon. The total binding energy of lithium-6 is around 31.8 MeV, while helium-4 is 28.3 MeV, for a difference between them of 3.5 MeV. So it actually took far less than 5.3 MeV to remove not just one, but two nucleons from lithium-6.

This is similar to removing electrons from their atomic orbitals. The first electron usually takes far less energy to remove than the next electron, which requires less energy to remove than the next electron, and so on... But the total energy required to remove the electrons from an atom is identical for all atoms of that type. We can take this total energy and divide by the number of electrons to get the binding energy per electron. While this doesn't tell us the amount of energy required to remove any specific electron, it immediately gives us an idea of how tightly bound the electrons are to the nucleus. An analogous situation occurs for nucleons and nuclei.

Does that make sense?
 
  • #7
Krushnaraj Pandya said:
Drakkith said:
The energy per nucleon required to completely disassemble the nucleus.

Still not clear to me, per nucleon as in we remove the nucleons one by one and add up all the energies required in each step? What's the difference between total binding energy then since it is also the energy required to disassemble the nucleus
Would it be clearer to say the following ?
The binding energy per nucleon is the average energy per nucleon that's required to completely disassemble the nucleus.​
.
 
  • #8
SammyS said:
Would it be clearer to say the following ?
The binding energy per nucleon is the average energy per nucleon that's required to completely disassemble the nucleus.​
.

Sure. I just don't talk good!
 
  • #9
Drakkith said:
Sure. I just don't talk good!
That made me chuckle !Your explanations were clear enough to me!
 
  • Like
Likes Drakkith
  • #10
Drakkith said:
It doesn't matter if you remove the nucleons one at a time or all at once. The total energy remains the same. The difference between the total binding energy and the binding energy per nucleon is right in their names. Total binding energy is the total amount of energy required. The binding energy per nucleon is the total divided by the number of nucleons.

Note that the actual energy you would spend to remove successive nucleons, one at a time, changes as you remove more and more nucleons. Consider lithium-6, with a binding energy of around 5.3 MeV per nucleon. If you remove a proton and a neutron you get helium-4, with a binding energy of around 7.075 MeV per nucleon. Thus the energy spent to remove successive nucleons must change, otherwise every element would have identical binding energy per nucleon. That is, if it took 5.3 MeV to remove every single nucleon, one at a time, from a nucleus of lithium-6, then after removing a proton and a neutron our binding energy per nucleon should still be 5.3 MeV. But it's not. It has risen to around 7 MeV. That means it took less than 5.3 MeV to remove that first nucleon. The total binding energy of lithium-6 is around 31.8 MeV, while helium-4 is 28.3 MeV, for a difference between them of 3.5 MeV. So it actually took far less than 5.3 MeV to remove not just one, but two nucleons from lithium-6.

This is similar to removing electrons from their atomic orbitals. The first electron usually takes far less energy to remove than the next electron, which requires less energy to remove than the next electron, and so on... But the total energy required to remove the electrons from an atom is identical for all atoms of that type. We can take this total energy and divide by the number of electrons to get the binding energy per electron. While this doesn't tell us the amount of energy required to remove any specific electron, it immediately gives us an idea of how tightly bound the electrons are to the nucleus. An analogous situation occurs for nucleons and nuclei.

Does that make sense?
Ah, that makes things much clearer- thank you :D
I understand the definitions clearly now.
SammyS said:
Would it be clearer to say the following ?
The binding energy per nucleon is the average energy per nucleon that's required to completely disassemble the nucleus.​
.
Thank you for clearing it up further,
the only thing I don't understand now is the conceptual reason behind why we calculate Q values to represent the energy (I'm always confused between whether the reactants have higher binding energy or the products in a fusion or fission reaction, or who has the higher rest mass etc. If there is an intuitive way to understand and keep track of the energetics I'd really appreciate it)
 
  • #11
Also a question that has perpetually confused me and that several people have given me different answers to is whether binding energy is positive or negative- By definition it is the energy required to break apart a nucleus and therefore should be positive but in nuclear reactions I saw it being compared to potential energy, such that in the products it becomes more negative and thus results in stability and release of energy(=Q), I don't understand which logic to follow
 
  • #12
Krushnaraj Pandya said:
Also a question that has perpetually confused me and that several people have given me different answers to is whether binding energy is positive or negative- By definition it is the energy required to break apart a nucleus and therefore should be positive but in nuclear reactions I saw it being compared to potential energy, such that in the products it becomes more negative and thus results in stability and release of energy(=Q), I don't understand which logic to follow

I believe binding energy is always positive by definition. But the difference in the binding energy between the reactants and products can be either positive or negative. It is this difference that determines whether or not you get a release of energy from a reaction.
 
  • #13
Drakkith said:
I believe binding energy is always positive by definition. But the difference in the binding energy between the reactants and products can be either positive or negative. It is this difference that determines whether or not you get a release of energy from a reaction.
So total binding energy of products should be higher (therefore, BE(products)-BE(reactants) should be positive) since it'd require more energy to break them (i.e. more stable), am I correct?
 
  • #14
Krushnaraj Pandya said:
So total binding energy of products should be higher (therefore, BE(products)-BE(reactants) should be positive) since it'd require more energy to break them (i.e. more stable), am I correct?

It depends on the reaction.
 
  • #15
Drakkith said:
It depends on the reaction.
For a spontaneous one?
 
  • #16
Krushnaraj Pandya said:
For a spontaneous one?

Then it will release energy, so the reactants have to have less binding energy than the products.
 
  • #17
Thank you very much, Its crystal clear now :D
 

Related to Calculating Binding Energy for C13 Neutron Removal

1. What is the definition of binding energy?

Binding energy refers to the amount of energy required to break apart the nucleus of an atom into its individual protons and neutrons.

2. How is binding energy calculated?

Binding energy is calculated by taking the mass defect (the difference between the mass of the nucleus and the sum of the masses of its individual particles) and multiplying it by the speed of light squared (c²) using the famous equation E=mc².

3. What is the significance of binding energy?

Binding energy plays a crucial role in nuclear physics as it determines the stability and strength of the nucleus. It also plays a role in nuclear reactions and processes such as nuclear fission and fusion.

4. How is binding energy related to the strong nuclear force?

The strong nuclear force is what holds the nucleus of an atom together. Binding energy is the manifestation of this force, as it is the energy required to overcome the strong nuclear force and break apart the nucleus.

5. Can binding energy be negative?

Yes, binding energy can be negative in certain cases, such as when the mass of the nucleus is less than the combined masses of its individual particles. This is known as a mass defect and can result in a negative binding energy value.

Similar threads

  • Introductory Physics Homework Help
Replies
3
Views
855
  • Introductory Physics Homework Help
Replies
12
Views
227
  • Introductory Physics Homework Help
Replies
5
Views
1K
  • Introductory Physics Homework Help
Replies
1
Views
798
  • Introductory Physics Homework Help
Replies
5
Views
1K
  • Introductory Physics Homework Help
Replies
21
Views
2K
  • Introductory Physics Homework Help
Replies
1
Views
1K
  • Introductory Physics Homework Help
Replies
1
Views
6K
  • Introductory Physics Homework Help
Replies
5
Views
1K
  • Introductory Physics Homework Help
Replies
3
Views
2K
Back
Top