Biot-Savart Law: Magnetic Fields on an equilateral triangle

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SUMMARY

The discussion focuses on applying the Biot-Savart Law to determine the magnetic field at the top vertex of an equilateral triangle formed by two current-carrying wires located at the lower corners. The magnetic field equations provided include dB=(μ_o Idlsinθ)/(4πr^2) and its differential form dB=(μ_{o}IdLx\hat{r})/(4πr^{2}). Participants clarify the geometry of the problem and emphasize the need to calculate the contributions from both wires, particularly in scenarios where the currents flow in different directions.

PREREQUISITES
  • Understanding of the Biot-Savart Law
  • Familiarity with vector calculus and integration
  • Knowledge of magnetic fields generated by current-carrying conductors
  • Basic principles of electromagnetism
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  • Study the application of the Biot-Savart Law in different geometries
  • Learn how to calculate magnetic fields from multiple current sources
  • Explore vector calculus techniques for solving integrals involving trigonometric functions
  • Investigate the effects of current direction on magnetic field orientation
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Students in physics, particularly those studying electromagnetism, as well as educators and anyone looking to deepen their understanding of magnetic fields generated by current-carrying wires.

alovesong
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Homework Statement



Two long straight wires sit at the lower corners of an equilateral triangle and carry current I. Find the magnitude and direction of the B field at the top vertex of the triangle for the case where:

a) the current in both lower wires flows out of the page
b) the current in the left wire flows out of the page, the current of the right wire flows into the page.


Homework Equations



dB=(μ_o Idlsinθ)/(4πr^2 ) for the magnetic field at a point P in space


The Attempt at a Solution



First, I don't really know what effect being physically connected to the current-bearing wires has on P. Assuming it's negligible, though, then working with just one wire

r= length of triangle side from P to current-bearing wire
R= distance directly from P to the wire?

B= (u_o*I/4π) integral[dlsinθ/r^2]

dl= R(csc^2θdθ = r^2dθ/R

B= (u_o*I/4πR) [int from θ=0 to π] sinθdθ = -(u_o*I/4πR)cosθ evaluated from 0 to π

This is based mostly around an example for another problem, but I think most of it applies... However I am confused on the integral boundaries (if it's an equilateral triangle, shouldn't θ be fixed at 60?) and am unsure how how incorporate the second wire. Help, please!
 
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I'm not sure if you have a correct picture of what's going on here in your head, because P is not connected to the current-bearing wires. Imagine an equilateral triangle. Now, the two lower VERTICES have wires passing through them perpendicular to the plane of the page with directions given in a) and b). This should help to simplify the problem into a point experiencing a force due to two magnetic fields from two wires.
 
Okay, yeah, you're right - for some reason I thought that the "equilateral triangle" was physical, when it's not... but I'm still confused about what to do with the two separate wires.
 
alovesong said:

Homework Equations



dB=(μ_o Idlsinθ)/(4πr^2 ) for the magnetic field at a point P in space

Well you're going to need to know how to calculate the magnetic field due to the wires, which it seems you need to do via biot-savart.
The biot-savart equation, in its differential form, is actually this:
dB=\frac{\mu_{o}IdLx\hat{r}}{4 \pi r^{2}}
Where \hat{r} is the unit vector in the direction of the point. Now, think about what the theta from the cross product represents, and you should be able to develop the general form for magnetic field a distance r away from a charge carrying wire. Hint: What is constant and what is changing?
 

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