Bit foggy on this trig question

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Homework Statement


arccos(cos2[tex]\Pi[/tex])




The Attempt at a Solution


cos of 2[tex]\Pi[/tex] =1
how do I get the arccos of 1? Without a calculator.
Thanks
 
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You have to use either some log tables or your memory. More specifically if you know how to sketch the graph of a cos function then you would know immediately that [tex]\cos (2\pi n) = 1[/tex] where n is any integer (including 0).
 
Yes, I know how to get cos of 2[tex]\Pi[/tex]. It equals 1
I don't know how to get arccos of 1.
Could you help me with that?

I know that, for instance arccos [tex]\stackrel{\Pi}{4}[/tex] = [tex]\stackrel{1}{\sqrt{2}}[/tex]

But how do I figure out arccos 1.

I know it = 0 but I can't see how to derive this
 
arccos is inverse function of cos. So If you know that cos(2п)=1 you will know that arccos(1)=2п. Do you understand now?

Regards.

P.S arccos(1 / √2) = п/4
 
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