yoleven Messages 78 Reaction score 1 Thread starter Dec 2, 2008 #1 Homework Statement arccos(cos2[tex]\Pi[/tex]) The Attempt at a Solution cos of 2[tex]\Pi[/tex] =1 how do I get the arccos of 1? Without a calculator. Thanks
Homework Statement arccos(cos2[tex]\Pi[/tex]) The Attempt at a Solution cos of 2[tex]\Pi[/tex] =1 how do I get the arccos of 1? Without a calculator. Thanks
Defennder Homework Helper Messages 2,590 Reaction score 4 Dec 2, 2008 #2 You have to use either some log tables or your memory. More specifically if you know how to sketch the graph of a cos function then you would know immediately that [tex]\cos (2\pi n) = 1[/tex] where n is any integer (including 0).
You have to use either some log tables or your memory. More specifically if you know how to sketch the graph of a cos function then you would know immediately that [tex]\cos (2\pi n) = 1[/tex] where n is any integer (including 0).
yoleven Messages 78 Reaction score 1 Dec 2, 2008 #3 Yes, I know how to get cos of 2[tex]\Pi[/tex]. It equals 1 I don't know how to get arccos of 1. Could you help me with that? I know that, for instance arccos [tex]\stackrel{\Pi}{4}[/tex] = [tex]\stackrel{1}{\sqrt{2}}[/tex] But how do I figure out arccos 1. I know it = 0 but I can't see how to derive this
Yes, I know how to get cos of 2[tex]\Pi[/tex]. It equals 1 I don't know how to get arccos of 1. Could you help me with that? I know that, for instance arccos [tex]\stackrel{\Pi}{4}[/tex] = [tex]\stackrel{1}{\sqrt{2}}[/tex] But how do I figure out arccos 1. I know it = 0 but I can't see how to derive this
Дьявол Messages 365 Reaction score 0 Dec 2, 2008 #4 arccos is inverse function of cos. So If you know that cos(2п)=1 you will know that arccos(1)=2п. Do you understand now? Regards. P.S arccos(1 / √2) = п/4 Last edited: Dec 2, 2008
arccos is inverse function of cos. So If you know that cos(2п)=1 you will know that arccos(1)=2п. Do you understand now? Regards. P.S arccos(1 / √2) = п/4
HallsofIvy Science Advisor Homework Helper Messages 42,895 Reaction score 983 Dec 4, 2008 #5 For any number, x, between 0 and [itex]\pi[/itex], arccos(cos(x))= x. That follows from the very definition of "arccos".
For any number, x, between 0 and [itex]\pi[/itex], arccos(cos(x))= x. That follows from the very definition of "arccos".