BJT Circuit Problem Find Vc Quickly

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SUMMARY

The forum discussion focuses on a BJT circuit problem where the voltage Vc is determined to be 3V. The solution assumes that the emitter voltage (VE) is 7V, leading to a collector current (IC) of approximately 3mA, which is equal to the base current (IB). The quick determination of Vc is attributed to the direct relationship between the collector current and the voltage drop across the collector resistor.

PREREQUISITES
  • Understanding of BJT (Bipolar Junction Transistor) operation
  • Knowledge of Ohm's Law and Kirchhoff's Voltage Law
  • Familiarity with circuit analysis techniques
  • Basic concepts of collector and emitter currents in transistor circuits
NEXT STEPS
  • Study BJT circuit analysis techniques in detail
  • Learn about the relationship between collector current (IC) and base current (IB)
  • Explore the impact of emitter voltage (VE) on transistor operation
  • Review examples of calculating voltage drops in transistor circuits
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Electrical engineering students, hobbyists working with transistor circuits, and anyone seeking to understand BJT operation and circuit analysis.

theBEAST
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Homework Statement


Here is the diagram and solution for the problem:
Odgr6wg.png


The only problem I have is how the solution was able to find the voltage Vc so fast. They got the answer 3V without showing any work?
 
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Were you told that VE = 7v? That means IE is 3mA. With IC practically equal to IB, that 3mA passes through the collector resistor to ground.
 

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