nanjo
- 18
- 1
Thanks , but I had already acknowledged a misunderstanding. Again, the observed spectrum is what I wanted and did get posts ago.Orodruin said:Then the answer to your original question is:
"The Lyman-alpha emitted wavelength is 121.567 nm.
You can easily compute the observed wavelength from the redshift value z = 2.219."
If you want the actual number, then ##1 + z = \lambda/\lambda_0## implies that
$$
\lambda = \lambda_0(1+z) = (121.567\ {\rm nm}) (1+2.219) \simeq 391.3\ {\rm nm}
$$
This is irrespective of whether you believe that the observed wavelength is 391.3 nm because the Universe expanded by a factor of 3.319 or not.