Black Holes & Particle Collisions: Does Linear Momentum Transfer?

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SUMMARY

The discussion centers on the conservation of linear momentum in the context of black holes, specifically regarding particle collisions with a black hole described by the Schwarzschild metric. It is established that while energy and angular momentum are conserved, the effect of linear momentum transfer from particles to a black hole remains uncertain. The inquiry raises the question of whether sufficient particle collisions can impart an impulse to a black hole, suggesting that a different metric may be required to analyze such scenarios, as the Schwarzschild metric assumes a static black hole state.

PREREQUISITES
  • Understanding of the Schwarzschild metric in general relativity
  • Knowledge of energy and angular momentum conservation laws
  • Familiarity with black hole physics and properties
  • Basic concepts of particle physics and collisions
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Physicists, astrophysicists, and students interested in black hole dynamics, general relativity, and the implications of particle interactions with massive objects.

apamirRogue
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Now I know that in the general Schwarzschild metric, there is energy and angular momentum conservation, but what I'm wondering is if there is any linear momentum conservation. Let's say a particle collides with a black hole. Does the energy of that particle go solely to the rest mass and temperature of the black hole, or does it impart a slight impulse to the black hole? In simpler terms, can you move a black hole by just shooting enough particles into it?
 
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A black hole is not an ordinary object, so many intuitions about how ordinary objects behave do not apply to black holes. In this particular case, I don't know that the question has been studied. The Schwarzschild metric describes a black hole whose state of motion does not change, so to speak; you would need a different metric to describe a hole which has enough particles shot into it to impart an impulse, if that's possible. I've never seen such a metric described, so I don't know if the answer to your question is known.
 
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