Bloch equations for a 3-level system

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The discussion focuses on deriving the Hamiltonian for a three-level quantum system under the influence of two light fields. The diagonal elements of the Hamiltonian are straightforward, but confusion arises regarding the off-diagonal elements, particularly why certain matrix elements, such as ##\langle 1 | H_I | 2 \rangle##, equal zero. The participants explore the dipole interaction Hamiltonian and the implications of the rotating wave approximation in this context. They seek clarification on how to properly apply the approximation and calculate the relevant matrix elements. Understanding these concepts is crucial for accurately modeling the dynamics of the three-level system.
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Homework Statement


"Consider a system with three states, ##|1\rangle , |2\rangle ,|3\rangle ## with energies ##\hbar \omega_1 , \hbar \omega_2 , \hbar \omega_3 ##. the states are then separated by ##\hbar \omega_3 -\hbar \omega_1 = \hbar \omega_{13}## and ## \hbar \omega_3-\hbar \omega_2= \hbar \omega_{23}##. Two separate light fields are incident on the system with frequencies ##\omega_p## and ##\omega_c## respectively, where ##\omega_p## couples states 1 and 3 with a detuning of ##\Delta_p##, and ##\omega_c## couples states 2 and 3 with a detuning of ##\Delta_c##. The loss rates from the excited states ##|2\rangle## and ##|3\rangle## are ##\gamma_2## and ##\gamma_3## respectively.

Show that the H for the system in the rotating wave approx. is ##
\dfrac{\hbar}{2}\begin{pmatrix}
2\omega_{1}& 0 & -\Omega_{p}e^{i\omega_{p}t} \\
0& 2\omega_{2} & -\Omega_{c}e^{i\omega_{c}t}\\
-\Omega_{p}e^{-i\omega_{p}t}& -\Omega_{c}e^{-i\omega_{c}t} & 2\omega_{3}
\end{pmatrix}##

Where the Rabi frequencies ##\Omega_p## and ##\Omega_c## are defined naturally, for example
## \hbar\Omega_{p} = \langle 1 |\vec{d} \cdot \vec{E_{p}}| 3 \rangle ##."

Presumably ##\vec{E_p}## is the vector magnitude of the relevant electric field, i.e. the field coupling state 1 and 3 is described by ##\vec{E_p}\cos (\omega_p t)##.

The Attempt at a Solution


The diagonal elements of the Hamiltonian are straightforward, but we don't understand why the off diagonals look the way they do. In the two-state case, the dipole interaction Hamiltonian is given by ##H_I = -\vec{d}\cdot \vec{E}## where our electric field is ##\vec{E} \cos (\omega t).## Then the off diagonal element is given by ##\langle 1 | H_I | 2 \rangle = \langle 2 | H_I | 1 \rangle ^* = - \langle 1 | \vec{d} \cdot \vec{E} | 2 \rangle \cos (\omega t). ## But in this case we have two electric fields and so ## H_I = -\vec{d} \cdot (\vec{E_p}\cos{w_pt} + \vec{E_c}\cos{w_ct})##. But when we try to take the matrix element of this w.r.t. the different states to find the entries of the Hamiltonian, things aren't working out. For example, why is it that ##\langle 1 | H_I | 2 \rangle = 0 ## ?
 
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