Block collidining with a spring

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SUMMARY

The discussion centers on calculating the work done by a spring when a 2.40 kg block compresses it by 5.00 cm, with a spring constant of 400 N/m and a coefficient of kinetic friction of 0.450. The correct approach involves using the work-energy principle, where the work done by the spring equals the change in potential energy. The user struggled with integrating the spring force, represented as kx, over the distance of compression, indicating a need for clarity on applying the work-energy theorem in the presence of friction.

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zhenyazh
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hi,
i am preparing for an exam and have a problem with the following question.
an image is attached.

A moving 2.40 kg block collides with a horizontal spring whose spring constant is 400 N/m.
The block compresses the spring a maximum distance of 5.00 cm from its rest position. The coefficient of kinetic friction between the block and the horizontal surface is 0.450. What is the work done by the spring in bringing the block to rest?

i am confused. tried to integrate kx on the 0 until 0.05 didn't work.
tried the same minus the friction force on that area. didn't work.

could some one explain in detail how it is done here?

thanks
 

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you can start from the fact that the work done by a conservative force which in your case is a spring force equals to the change in potential energy ..


I hope now it is clear enough for you to start ..
 
zhenyazh said:
i am confused. tried to integrate kx on the 0 until 0.05 didn't work.
That should work just fine--show how you did the integration.
 

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