Block hitting a spring down an incline

  • Thread starter AnkhUNC
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  • #1
AnkhUNC
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Homework Statement


In Fig, a block of mass m = 19 kg is released from rest on a frictionless incline of angle θ = 34°. Below the block is a spring that can be compressed 4.5 cm by a force of 210 N. The block momentarily stops when it compresses the spring by 3.6 cm. (a) How far does the block move down the incline from its rest position to this stopping point? (b) What is the speed of the block just as it touches the spring?

http://edugen.wiley.com/edugen/courses/crs1650/art/qb/qu/c08/fig08_41.gif


Homework Equations





The Attempt at a Solution



I found (a) = 0290429321 meters which is correct.
For (b) I tried the following v = sqrt(K*.036m^2)/19kg. But this is also incorrect. Any ideas?
 

Answers and Replies

  • #2
Shooting Star
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I found (a) = 0290429321 meters which is correct.
For (b) I tried the following v = sqrt(K*.036m^2)/19kg. But this is also incorrect. Any ideas?

No decimal point for (a)?

For (b), your approach is correct, but I'm unable to make out if the sqrt covers the 19 in the denominator.
 

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