Block Movement Dynamics: Solving for Time, Acceleration, and Distance

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SUMMARY

The discussion centers on solving a physics problem involving a block of mass m on a rough horizontal surface, influenced by a time-varying force F(t) and friction. The user seeks to determine the time t2, acceleration a2, and distance s2 after the force ceases. Key calculations include using the impulse formula to find the speed v1 at t1 as 4.346 m/s and deriving t2 as 0.394 seconds, leading to a total time of 1.808 seconds. The user also mentions the need to create acceleration, velocity, and time diagrams for a comprehensive analysis.

PREREQUISITES
  • Understanding of Newton's laws of motion
  • Familiarity with impulse and momentum concepts
  • Knowledge of kinematics equations
  • Basic proficiency in calculus for integration
NEXT STEPS
  • Study the principles of impulse and momentum in physics
  • Learn how to derive kinematic equations for motion under constant acceleration
  • Explore the effects of friction on motion, particularly in rough surfaces
  • Practice drawing and interpreting acceleration, velocity, and time diagrams
USEFUL FOR

Students studying physics, particularly those focusing on mechanics, as well as educators seeking to enhance their understanding of block movement dynamics and related calculations.

Preach99
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Homework Statement


Hi guys. First of all, great forum you've got here.

I have a problem and I hope you can help me with this one.

Block of mass m lies on a rough horizontal surface. In the period 0 - t1, the block is moving due to the force F(t), which varies depending on the time. In period t1 - t2 we only have friction (F=0), and the block in the time t2 has speed v2=1 m/s. I have to find time t2, acceleration in t2 (a2) and distance s2. I also have to draw a, v, t diagrams.

Homework Equations



m2v⃗ -m1v⃗ 1=∫F(t)⃗ dt


The Attempt at a Solution



9q9w6b.jpg


my formula in mathcad

uvvx3.jpg


I'm stuck with this integration. I understand that the first part (F*cos(60°)) is the area under the curve - √2 *m*g

I hope you guys can help. Thank you in advance.
 
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wow, 400 views and no reply lol

I was quite busy today but I tried a different approach.
First, I only calculated the part from 0 to t1 with that Impulse formula and the speed v1 (@ t1) is 4.346 m/s.

Then, since the force is F=0, I have Fn=m*g (y axis), and Frx=-μ*m*g (x axis).
And when I try to calculate this part, I get a weird result -> t2=0.394 s lol.
IDK, this could only make sense if the real t2 time would be √2+0.394=1.808 seconds

:blushing:
 

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