Block of ice on frictionless surface

[rebeccc]

A 1.6 -long, 550 rope pulls a 9.0 block of ice across a horizontal, frictionless surface. The block accelerates at 1.0 .

1) How much force pulls forward on the block of ice?

2) How much force pulls forward on the rope?

 

[mgb_phys]

Welcome to PF - please have an attempt at the question.
What equations do you know, what are the units?
What forces are acting ?

 

[baba89]

I would respond by saying that the amount of force pulling forward on the block of ice can be calculated using Newton's Second Law of Motion, which states that force equals mass multiplied by acceleration (F=ma). In this scenario, the mass of the ice block is not given, but we can assume that it is constant. Therefore, the force pulling forward on the ice block can be calculated by multiplying the mass of the block by its acceleration, which is 1.0 m/s^2. This means that the force pulling forward on the block of ice is 9.0 N (9.0 kg x 1.0 m/s^2).

As for the force pulling forward on the rope, it is important to understand that the rope is not an object that can exert force on its own. Instead, the force pulling forward on the rope is being applied by an external source, such as a person or a machine. In this case, the force pulling forward on the rope is equal to the force pulling forward on the block of ice, which is 9.0 N. This is because, according to Newton's Third Law of Motion, for every action there is an equal and opposite reaction. So, the force pulling forward on the rope is equal to the force pulling forward on the block of ice, but in the opposite direction.