Block sliding down a wedge, all resting on a balance

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SUMMARY

The discussion focuses on the dynamics of a block sliding down a wedge, specifically analyzing the net force acting on the block, the force exerted by the block on the wedge, and the conditions required for the wedge to remain stationary. The net force on the block is non-zero due to its acceleration down the incline. The force exerted by the block on the wedge is a two-dimensional vector, comprising both horizontal and vertical components. For the wedge to remain stationary, the horizontal component of the force must be balanced by the reaction force from the ground. Additionally, the reading on the balance will indicate the weight of the block adjusted for its acceleration.

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  • Understanding of Newton's laws of motion
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dorothy
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Homework Statement
Hello! I am now working on an exercise which is related to mechanics. I calculated it wrongly. Attached is the answer. I have no idea how to do c(ii), I don’t understand how cos theta is applied in that question. Please explain it to me if you get it. thanks a lot!
Relevant Equations
F=ma
a=mg*sin theta
IMG_0130.jpeg
IMG_0131.jpeg
 
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Consider the wedge block sliding down on the rough incline. Please answer the following three questions which are an elaboration of the hint in c(ii).
  1. What is the magnitude and direction of the net force on the sliding block? It cannot be zero because the block is accelerating.
  2. What is the force exerted by the block on the wedge? It must be a 2D vector with horizontal and vertical components.
  3. What must be true for the wedge to remain stationary?
Bonus question: What is the reading of the balance when the block is accelerating?
 
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