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**1. Homework Statement**

There is a 5.0kg block sliding 1.5m down an inclined plane 12 degrees from the horizontal. the coefficient of kinetic friction is 0.310. Whats is the work done on the block by friction and gravity?

**2. Homework Equations**

F=ma, W=fd, fk=uk*N

**3. The Attempt at a Solution**

So, i calculated the frictional force to be [tex]mgcos(12)\mu_{k}[/tex], but when i found the component force of gravity in the opposite direction ([tex]mgsin(12)[/tex]), i found that the force of friction was bigger than it. I think im just overlooking something major, but i cant see what i did wrong.