Boolean algebra simplification ?

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KaliBanda
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Homework Statement



Boolean expression Y = (((overline(B + C) + overline(A)) + C) with the overline covering the B + C group and the A term, written as typeset math.


Homework Equations



DeMorgan’s Theorems.

The Attempt at a Solution



Handwritten Boolean algebra simplification steps applying De Morgan's theorems, showing Y = (((B+C)+A)+C) lines rewritten through (B+C)A, AB, AC and finally (B+A+C) style forms ending in Y = (B + A + A-bar + C-bar) C-bar.


I've had a go at it, not sure if I'm heading in the right direction though.

Thanks for any help.
 
Where does the second + in line 4 come from? I would expect * there, as you had it in line 3.
Anyway, I would use another direction there:
##(\overline{AC})\overline{C}## has a nice simplification.