- #1

- 33

- 0

## Homework Statement

Simplify the following expressions

(x'y'+xy'+x'y)

(p+q'p)(p+qr)

## Homework Equations

Laws of boolean algebra

## The Attempt at a Solution

For the first one I've found many ways to solve it... something isn't right here

(x'y'+xy'+x'y)

=x'(y'+y)+xy'

=x'+xy'

=x'+x+y'

=y'

OR

=y'(x'+x)+x'y

=y'+x'y

=y'+x'+y

=x'

I'm definantly doing something wrong here... probably making up laws

For the second I'm not sure if the last line is even possible

(p+q'p)(p+qr)

=pp+pqr+ppq'+q'qr

=p+pqr+pq'+0

=p+pqr

=p? Can I do that with pqr having 3 variables?