Yes. And the reason is at the boundary the most you will get is a surface charge density ## \sigma_p ##. The electric field from an infinite sheet of surface charge, which is what ## \sigma_p ## will look like at very close range is finite, even though the field from the surface charge will point in opposite directions on opposite sides of the sheet of surface charge. Thereby, the change in potential as one traverses an infinitesimal distance across the boundary of surface charge is also infinitesimal. (The electric field sees a discontinuity as one crosses the boundary, but not the potential.)