- #1
francescalynn
- 3
- 0
In order to get an appreciation for the time scales involved, think about a block that slides without friction down a ramp that is inclined at an angle q above the horizontal. Initially the block is at rest a distance s (measured along the plane) from the bottom. Click the button marked “DATA” for specific values of q and s. (Remember these numbers; you will need them later.) Calculate the time required for the block to slide to the bottom.
For my given values I have: distance, s = 306 m, and q = 11 deg
To find the time it takes for the block to slide to the bottom, I tried:
d = 306sin(11) = 58.4 m
d = v0t - 1/2at^2
58.4 = 0 - 1/2(-9.8)t^2
t = 3.45017
and
1/2mv^2 - 1/2mv0^2 = F*d
1/2v^2 - 1/2(0)^2 = a*d
1/2v^2 = -9.81(-306sin(11))
v = 33.38289 m/s
v = v0 + at
t = 3.44898
For my given values I have: distance, s = 306 m, and q = 11 deg
To find the time it takes for the block to slide to the bottom, I tried:
d = 306sin(11) = 58.4 m
d = v0t - 1/2at^2
58.4 = 0 - 1/2(-9.8)t^2
t = 3.45017
and
1/2mv^2 - 1/2mv0^2 = F*d
1/2v^2 - 1/2(0)^2 = a*d
1/2v^2 = -9.81(-306sin(11))
v = 33.38289 m/s
v = v0 + at
t = 3.44898