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misskitty
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I'm working through a definite integration with a secant function as my antiderivative...the secant is 1/cos right?
~Kitty
~Kitty
Yes, and 1/sin(x) is cosec(x) = csc(x).misskitty said:I'm working through a definite integration with a secant function as my antiderivative...the secant is 1/cos right?
~Kitty
That's ok, as well as doing 1/sin(x) immediately, just as long as you don't use the [itex]\sin^{-1}[/itex] button, since that's inverse sine and not 1/sin.misskitty said:Right. What I do when I have 1/sin x questions is I do the trig first so the sin x then once I have that answer I divide one by the answer I get. Is that still wrong?
~Kitty
No idea, unless I'm misunderstanding you.misskitty said:Why did he tell me I was doing this wrong? I explained my process exactly as I just did to you.
~Kitty
Okay, what do you get for 1 / (sin(2.5)) (in radians mode)?misskitty said:No I don't think you are.
The only other thing I can't figure out is why I keep getting the incorrect answer because I'm following the process of the Fundamental theorem of calculus the way my book tells me too down to the letter. Is there some reason why this keeps happening?
~Kitty
misskitty said:This might look kinda messy but this is one of the problems I've been working on sec^2xdx in the intervale of -pi/6 < x < pi/6. Does that make sense?
~Kitty
Hmmm, not sure what you mean... What does the problem ask? What's the question?misskitty said:This might look kinda messy but this is one of the problems I've been working on sec^2xdx in the intervale of -pi/6 < x < pi/6. Does that make sense?
~Kitty
[tex]\int \sec ^ 2 x dx = \tan x + C[/tex]misskitty said:The problem is evaluating the definite integral.
BTW- I think my calculator might round automatically causing the .02 difference.
~Kitty
I get about 1.1547, so your answer seems correct. The book may be wrong. However, you should watch out for rounding error.misskitty said:That exactly what I did to solve the problem. What did you come up with for an answer? My answer is 1.158 but the book says its wrong.
~Kitty
One big hint:misskitty said:2( square root of 3)/ 3 I believe they are equivalent answers. I think they might have mislabled the answers again. This book is notorious for doing that.
~Kitty
Arrgghh, you've misinterpreted my post.misskitty said:I get how to do it and that is the process that I used exactly. I just need to know if my answer is correct. That example does tell me I'm going through the correct process though. I was walking blind through the book.
~Kitty
misskitty said:Oh sorry. If you rationalize that it turns out to be 2(square root of 3)/ 3...
~Kitty
?Hootenanny said:Why have you multiplied by 2/1? That has changed the fraction. Once you have mulitplied by [itex]\frac{\sqrt{3}}{\sqrt{3}}[/itex] the fraction is now rational. When you mulitplied by [itex]\frac{2}{1}[/itex] you changed the fraction!
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