Trig Substitution Problem w/ tan substitution

Click For Summary

Homework Help Overview

The discussion revolves around a trigonometric substitution problem, specifically involving the use of tangent substitution. Participants are examining the original poster's attempt to solve the problem and the associated trigonometric identities.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • The original poster shares their attempt at a solution, including a visual representation. Some participants question the accuracy of the trigonometric identities used, particularly regarding the presence of a square root in the formula for cosecant. Others challenge the understanding of triangle dimensions in relation to Pythagoras' Theorem.

Discussion Status

The discussion is ongoing, with participants providing feedback on the original poster's work. There is a mix of clarifications and corrections being offered, but no consensus has been reached regarding the correct approach or solution.

Contextual Notes

There is a mention of the original poster's fatigue affecting their work, which may have contributed to the errors identified in their solution. The discussion highlights potential misunderstandings about trigonometric relationships and triangle properties.

Burjam
Messages
52
Reaction score
1

Homework Statement



Under #3

Homework Equations



Trig identities

The Attempt at a Solution



The picture attached is my attempt. The square in the upper upper left is the problem and the one in the lower right is my solution. I'm seeing that I'm getting the wrong answer, but not how.

1479619739190-1775315430.jpg
 
Physics news on Phys.org
You should type in the problem at least.
The formula for csc (theta) is wrong, You miss a square root.
 
  • Like
Likes   Reactions: fresh_42
I miss a square root? Where does a square root come into play? None of the sides of the triangle should have a square root in them.
 
Burjam said:
I miss a square root? Where does a square root come into play? None of the sides of the triangle should have a square root in them.
Really? So the dimension of the sides of a right triangle is length, but that of the hypotenuse is length-squared?
Recall Pythagoras' Theorem.
 
Haha sorry I did this while really tired... my bad.
 

Similar threads

Potential of a rotationally symmetric charge distribution
  • · Replies 4 ·
Replies
4
Views
2K
Using hyperbolic substitution to solve an integral
  • · Replies 18 ·
Replies
18
Views
4K
Indefinite Integral: How to Use Trig Substitution?
  • · Replies 1 ·
Replies
1
Views
2K
Trigonometric substitution of (x^2+8x)
  • · Replies 4 ·
Replies
4
Views
2K
Why Does Trig Substitution Yield Different Integral Results?
  • · Replies 3 ·
Replies
3
Views
2K
Integration by substitution u=tan(t)
  • · Replies 7 ·
Replies
7
Views
2K
Nasty Integral - Help with Trig Substitution
  • · Replies 3 ·
Replies
3
Views
2K
Integrate √1+x^2 - Solutions & Explanations
  • · Replies 2 ·
Replies
2
Views
1K
Solving an Integral Problem with Trig Substitution
  • · Replies 4 ·
Replies
4
Views
2K
How do I know what to substitute(u-substitution)
  • · Replies 3 ·
Replies
3
Views
2K