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JasonJo

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When a bushel of wheat is worth 9 lire, the bakers make a loaf of bread weighing 6 ounces, when a bushel of wheat is worth 11 lire, how big is a loaf of bread? (the price of a loaf is constant)

from Trevisio Arithmetic

here is how i approached it, tell me if I'm wrong:

let there be n ounces in a bushel. therefore 1 bushel = n/6 loaves therefore 9/(n/6) = price per loaf, and since this is constant, let it equal c. then if a bushel of wheat is equal to 11 lire, then 11/(n/x) = c where x is the weight of each loaf. therefore 11/(n/x) = 9/(n/6) and we get that x=54/11

is this right?

from Trevisio Arithmetic

here is how i approached it, tell me if I'm wrong:

let there be n ounces in a bushel. therefore 1 bushel = n/6 loaves therefore 9/(n/6) = price per loaf, and since this is constant, let it equal c. then if a bushel of wheat is equal to 11 lire, then 11/(n/x) = c where x is the weight of each loaf. therefore 11/(n/x) = 9/(n/6) and we get that x=54/11

is this right?

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