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Note: This is not a homework or coursework, simply revision for an exam. Thanks

[PLAIN]http://img194.imageshack.us/img194/223/question2z.jpg [Broken]

Peak voltage = RMS voltage x root2

r = T/(2RlC)

T = 1/f

part d)

Peak Supply Voltage = 240 x root2 = 339.41V

Peak Va = 339.41 x 0.1 = 33.941V

Peak Vb = 33.941 - 0.7 = 33.241V (uncertain about this one)

part e)

r=10%=0.1 T=1/50 Rl=200ohms

.:.

r = T/(2RlC)

0.1 = 0.02/400C

40C = 0.02

C = 5x10-4F

## Homework Statement

[PLAIN]http://img194.imageshack.us/img194/223/question2z.jpg [Broken]

## Homework Equations

Peak voltage = RMS voltage x root2

r = T/(2RlC)

T = 1/f

## The Attempt at a Solution

part d)

Peak Supply Voltage = 240 x root2 = 339.41V

Peak Va = 339.41 x 0.1 = 33.941V

Peak Vb = 33.941 - 0.7 = 33.241V (uncertain about this one)

part e)

r=10%=0.1 T=1/50 Rl=200ohms

.:.

r = T/(2RlC)

0.1 = 0.02/400C

40C = 0.02

C = 5x10-4F

## Homework Statement

## Homework Equations

## The Attempt at a Solution

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