Brightness of lightbulb concept questions

jakeddong
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So I googled and found out that brightness of a lightbulb is directly related to current, but for some reason it doesn't match the concept I have in my head.

I know that a lightbulb gets brighter as it gets hotter (like any kind of metal)
So for a lightbulb to get brighter, it needs more energy(for heating)
However this energy comes from the loss of kinetic energy of electrons as they pass through the resistors.
So if you increase the resistance, your lightbulb should get hotter and brighter because electrons lose more kinetic energy at higher resistance.
But according to the formula V=IR, if you increase resistance, the current decreases, which doesn't fit with what I found through google.

Could you tell me what is wrong in my reasoning?
 
on Phys.org
It is true that increasing the resistance to current would increase the brightness of the filament glow as it undergoes blackbody radiation. Yet the heat generated from the release of electron kinetic energy would be tremendous and instantly snuff out the part where it is connected. The reason why current would drop was because it did not even travel through the conductor due to resistance.

The reason that the brightness would increase with current comes from the equation

P= I^2*R
making P proportional to I if R constant

as long as your resistance remains constant, the determinant factor would be current.

That's what I have in mind though
 

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