Bringing 3 Charges from infinity into a triangle

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SUMMARY

The work required to arrange three charges, Q, into an equilateral triangle with side length 'a' is calculated using the formula U = (3kQ^2)/a. The first charge, Q1, requires no work to bring from infinity. The second charge, Q2, requires work calculated as U = (kQ^2)/a, and the third charge, Q3, requires additional work due to interactions with both Q1 and Q2, resulting in U = (2kQ^2)/a. The total work done is thus confirmed to be (3kQ^2)/a.

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  • Understanding of electrostatic potential energy
  • Familiarity with Coulomb's law
  • Knowledge of equilateral triangle geometry
  • Basic algebra for manipulating equations
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Homework Statement



How much work is needed to arrange three charges, Q, into an equilateral triangle? The particles are initially infinitely far apart. Take 'a' to be the length of each side of the triangle.

Homework Equations



U = {(kqq)/L}

The Attempt at a Solution



I was under the assumption it takes no work to bring the first charge, Q1, from infinity since no other force is present.

To bring in charge #2 requires:

U = (kQ1Q2)/a = (kQ^2)/a

To bring in charge #3 requires a greater U since two charges are already present. I added the two pair-wise interactions of Q1 with Q3, and Q2 with Q3:

U = (kQ1Q3)/a + (kQ2Q3)/a = (2kQ^2)/a

Add both U's and get:

(3kQ^2)/a

------

Is this correct?
 
Physics news on Phys.org
Yes, it is correct.

ehild
 

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