Bucklig: deflection at Euler load

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SUMMARY

This discussion focuses on calculating the horizontal deflection of a vertical clamped beam subjected to both horizontal and vertical loads. The user calculated the Euler buckling load for a beam of length 6 m and stiffness EI = 1476600 Nm², determining P_{cr} to be 101.20 kN, while applying a vertical load P of 5000 kN. Despite expectations that deflection would diverge beyond the Euler buckling load, the calculations converged to a deflection of 5.08259 * 10^{-5} m. The conversation highlights the need to consider beam-column behavior when lateral and axial loads are applied simultaneously.

PREREQUISITES
  • Understanding of Euler buckling load calculations
  • Familiarity with beam-column theory
  • Knowledge of structural mechanics, particularly deflection analysis
  • Proficiency in using formulas for deflection under combined loading conditions
NEXT STEPS
  • Research methods for analyzing beam-columns under combined lateral and axial loads
  • Study the modifications to Euler's critical load for lateral loading scenarios
  • Explore advanced deflection calculation techniques for clamped beams
  • Review literature on the effects of lateral loads on deflection in structural engineering
USEFUL FOR

Structural engineers, civil engineering students, and professionals involved in the design and analysis of beam-columns under complex loading conditions will benefit from this discussion.

Jef124
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Hello

I was trying to calculate the horizontal deflection of the free end of vertical clamped beam. The beam would be loaded at the free end with a horizontal force H and a vertical force P. My idea was to calculate an initial deflection due to the force H. Then calculate the additional deflection due to the previous deflection and the force P. I'd expect that when the force P is bigger than the Euler buckling load that the deflection would diverge but that's not happening when I try to calculate this.

I tried it on a beam with a length L of 6 m, stiffness EI = 1476600 Nm^2 (E=69 GPa, I=2140 *10^4 mm^4, H=1 kN. I calculated that the Euler buckling load P_{cr}=(Pi)^2EI/(2L)^2=101,20 kN and used a way bigger P=5000 kN.

For the initial deflection I used v_0=(1/3EI)HL^3=4,87607 *10^{-5} m. For the next iteration steps I used v_i=v_0 + (1/3EI)L^2P*v_{i-1} which eventually converges to v=5,08259 * 10^{-5} m instead of diverging.

I know 5000 kN isn't a realistic value and that the beam would probably yield with such a high load but shouldn't this diverge?

Also for loads smaller than the Euler buckling load, is this the right way to calculate the deflection? If not what would be a good way then?

Thanks in advance
 
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Jef124 said:
Hello

I was trying to calculate the horizontal deflection of the free end of vertical clamped beam. The beam would be loaded at the free end with a horizontal force H and a vertical force P. My idea was to calculate an initial deflection due to the force H. Then calculate the additional deflection due to the previous deflection and the force P. I'd expect that when the force P is bigger than the Euler buckling load that the deflection would diverge but that's not happening when I try to calculate this.

I tried it on a beam with a length L of 6 m, stiffness EI = 1476600 Nm^2 (E=69 GPa, I=2140 *10^4 mm^4, H=1 kN. I calculated that the Euler buckling load P_{cr}=(Pi)^2EI/(2L)^2=101,20 kN and used a way bigger P=5000 kN.

For the initial deflection I used v_0=(1/3EI)HL^3=4,87607 *10^{-5} m. For the next iteration steps I used v_i=v_0 + (1/3EI)L^2P*v_{i-1} which eventually converges to v=5,08259 * 10^{-5} m instead of diverging.

I know 5000 kN isn't a realistic value and that the beam would probably yield with such a high load but shouldn't this diverge?

Also for loads smaller than the Euler buckling load, is this the right way to calculate the deflection? If not what would be a good way then?

Thanks in advance

I'm just taking a quick glance at the situation you are trying to analyze here.

The usual formulas for the Euler buckling load are derived assuming that the only force applied is applied in the axial direction. I think the situation you are describing here is for what is called the buckling of a beam-column, since lateral and axial loads are being applied simultaneously to the tip of the cantilever. The Euler critical load must be modified in this case over that calculated for a simple column with no loads applied in the lateral direction.

There are methods for analyzing such beam-columns, but it will take a little research to confirm what is required.
 
Further to the discussion in Post #2 above, this article discusses the effect on the deflection of a laterally loaded member caused by an axial load. See pp. 5-6 for a discussion of the effect:
 

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I didn't realize I couldn't use Euler buckling for my situation. Thank you!
 

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