Buffer Solutions: How to Create and Maintain Optimal pH Levels?

AI Thread Summary
To create buffer solutions, a weak acid or base and its salt are necessary, but the discussion reveals confusion about the components needed. Reaction 1 produces a strong acid and a weak base, while Reaction 2 involves a strong base and a weak acid, leading to the conclusion that it does not form a buffer. Reaction 3 is identified as a potential buffer solution due to the presence of both a weak acid and its conjugate base, allowing for proton acceptance or donation. The participants clarify that a buffer requires comparable amounts of the conjugate acid and base, leading to a revised understanding of Reaction 2 as also capable of forming a buffer. The discussion emphasizes the importance of equilibrium shifts in determining buffer capacity.
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Homework Statement


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Homework Equations

The Attempt at a Solution


From what I know, to make buffer solutions you need a weak acid or base and it's salt. Non of the options has this. What am I missing?

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What is left after the reaction?
 
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For reaction 1, the products are: Cl-, NH4+, NH3, H+ (as HCl is strong acid while ammonia is weak base)
For reaction 2, the products are: Na+, H2O, NO2- (NaOH is strong while nitrous acid is weak. No HNO2 because the H+ will react to form water so equilibrium will shift to the right in equilibrium HNO2 → H+ + NO2-)
For reaction 3, the products are: NH3, NH4+, HNO2, NO2- (both are weak)

Reaction 3 is probably creates a buffer solution as they can accept or donate protons and the equilibrium will shift.
If acid was added to reaction 2, the NO2- will turn to nitrous acid but if base was added, nothing will happen, so not a buffer solution.
If acid was added to reaction 1, the equilibrium NH3 + H+ ↔ NH4+ will shift to the right and if base was added, the equilibrium will shift to the left so it is a buffer solution.

Answer is D.

Are my explanations correct?

Cheers!
 
Nope, you need a comparable amounts of conjugate acid and base for the buffer to exist.
 
I see, I change my mind on reaction 2. There will be around 0.5 M of HNO2 and NO2- so it will be a buffer solution. So then the answer is E?

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What is present after the reaction in the 3rd mixture?
 
NH3, NH4+, HNO2, NO2-
 
In what (approximate at least) concentrations?
 
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