Building a Marble Catapult

AI Thread Summary
To launch a marble 2-2.5 meters using a catapult with a 10 3/8 inch height and a 42-degree angle, the current spring compression of 1 inch yields a launch distance of 71 inches in 0.76 seconds. To achieve the desired distance, further experiments are suggested to gather data and assess the system's efficiency, as losses may significantly affect performance. The energy required for the launch must be derived from the spring, and factors such as the marble's parabolic trajectory, launch angle, and time of flight need to be calculated. The relationship between spring compression and energy storage is also crucial, with considerations on whether energy is proportional to the compression length or its square. A 45-degree launch angle is recommended for more consistent results, despite the current choice of 42 degrees.
bananamanz
Messages
1
Reaction score
0
Thread moved from the technical forums to the schoolwork forums
TL;DR Summary: I'm trying to solve how far to compress a spring to launch a marble 2-2.5m

I currently have a catapult built with a total height of 10 3/8 inches. The catapult tube is angled at 42 degrees and when the set spring inside the catapult is compressed by 1 inch the marble is launched 71 inches in 0.76 seconds. I am trying to find out how far back to compress the spring to get my desired distance of 2-2.5 meters.
 
Physics news on Phys.org
Is this a homework problem?
You've done one experiment, perhaps you could do some more to collect a data set to examine.
 
Agree. This is probably not an ideal system, and you don't know how to model the losses in your actual system, which are probably considerable.

That said, you could compute the increase in compression you need in the ideal case. That would be a lower bound on what you need in reality, so you might be able to determine if it's probably impossible with your existing spring.
 
bananamanz said:
I am trying to find out how far back to compress the spring to get my desired distance of 2-2.5 meters.
The energy needed to cover that distance must come from the spring.
The marble will have a parabolic trajectory, beginning and ending with your preset launch angle. (I assume takeoff and landing are at the same height).
The horizontal velocity component is fixed at launch.
The vertical velocity is changed by gravity during the flight.
How long in time must the marble fly?
What height must the marble reach to remain airborne for that distance?
How much energy is stored in a spring as it is compressed? Is energy proportional to length, or to length squared?

Why 42°, I would have chosen a 45° launch angle to get more consistent range results and make the arithmetic simple.
 
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Back
Top