bullet and pendulum bob....initial speed...help! momentum. 1. The problem statement, all variables and given/known data An 7.0 g bullet is fired into a 3.5 kg pendulum bob initially at rest and becomes embedded in it. If the pendulum rises a vertical distance of 8.0 cm, calculate the initial speed of the bullet. ________m/s 2. Relevant equations well there's many ways to do it, but heres one way: v=sqrt((1+M/m)*2gh) i tried it another way too, and got the same answer that i did with the above equation 3. The attempt at a solution so first, 7g bullet = .007kg bullet and height of 8cm = .08m ok so then v=sqrt((1+3.5/.007)*2*9.8*.08) = ~28.03 m/s now, i tried this TWO WAYS and got the same answer. but webassign says it's wrong. why?