Bullet hitting stationary Target.

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SUMMARY

A bullet with a mass of 0.005 kg traveling at 20 m/s penetrates a stationary target and comes to rest in 0.01 seconds. The calculated acceleration is 2000 m/s², and the distance penetrated is 30 cm. The discussion confirms that the bullet's acceleration is negative, as it decelerates while entering the target. The approach to solving the problem is validated, emphasizing the importance of considering the direction of acceleration.

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A bullet of 0.005 kg traveling at 20m/s penetrates deeply into a fixed target and is brought to rest in 0.01 sec. The distace through which it penetrates is:

I used,

acceleration= V/t
= 20/.01
a = 2000 m/sec sq

Distace covered = Ut+0.5 at^2
= 20*0.01+0.5*2000*(o.o1)^2
S= 30cm.

Is it correct or any other solution is possible..?
 
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The initial speed and the acceleration have opposite directions.
 
@willem2:

How is tat? can you please elaborate.
 
Does the bullet slow down or speed up as it moves through the block? So is acceleration positive or negative?
 
Acceleration reduces as the bullet enters the target.
 
so acceleration is negative...
 
Adarshaero said:
so acceleration is negative...

The velocity reduces as it passes through the target. So yes, acceleration is negative (in the direction opposite to the velocity).
 
I understand ur point. So is the approach right? And how about answer?
 
The approach is fine. How about the answer? Have you calculated one with the new knowledge about the acceleration direction?
 

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