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ln(β)=exp(A1 + A2*(T/100) + A3*ln(T/100) + A4*(T/100) + S*(B1 + B2*(T/100) + B3*(T/100)^2

where β is in units of mL/L, and A# and B# are empirically derived least square fit constants, different for specifics gases. My question is how to relate mL/L solubility to mg/L or mol/L of the specific gas in solution, say of oxygen in water. Any help would be appreciated! Thanks!