Buoyance Force & Centripital Motion

  • Context: Graduate 
  • Thread starter Thread starter Right
  • Start date Start date
  • Tags Tags
    Force Motion
Join the discussion
Ask a follow-up here, or get your own question answered by working scientists, mathematicians and engineers — people, not an autocomplete.
Real named experts · corrections over time · the nuance an AI answer skips
8 replies · 2K views
Right
Messages
5
Reaction score
0
Hello my fellow movers of the Earth!

Could someone who knows better tell me: If a centrifuge were spinning so fast as to produce 1g of centripetal force (net 1g downward + 1g outward), would the bubbles/air in spherical vessels sitting in the centrifuge travel equally inward as upward? Directions relative to the center of the centrifuge.
If so, would the magnitude of buoyant force be √2 of the normal buoyant force (centrifuge off)?

Thanks peeps!
 
Last edited:
Physics news on Phys.org
Right said:
If a centrifuge were spinning so fast as to produce 1g of centripetal force (net 1g downward + 1g outward), would the bubbles/air in a spherical vessel travel equally inward as outward?
A spherical vessel? Is this vessel spinning like a top? Or sitting in a spinning centrifuge? Are "inward" and "outward" to be taken with respect to the center of the sphere or the axis of rotation of the centrifuge?
 
jbriggs444 said:
A spherical vessel? Is this vessel spinning like a top? Or sitting in a spinning centrifuge? Are "inward" and "outward" to be taken with respect to the center of the sphere or the axis of rotation of the centrifuge?

Sorry, that was obscure. Spherical vessel(s) sitting in a spinning centrifuge. And yes, inward with respect to the center of the centrifuge. Will edit for clarity.

And also found a typo - Outward was meant to be upward.
 
Right said:
Could someone who knows better tell me: If a centrifuge were spinning so fast as to produce 1g of centripetal force (net 1g downward + 1g outward), would the bubbles/air in spherical vessels sitting in the centrifuge travel equally inward as upward?
Yes.

Right said:
If so, would the magnitude of buoyant force be √2 of the normal buoyant force (centrifuge off)?!
Yes, but the apparent weight (gravity + centrifugal force) of floating objects or gas bubbles would also be √2 of gravity alone. So they wouldn't submerge less or float faster upwards than normally.
 
Last edited:
A.T. said:
Yes, but the apparent weight (gravity + centrifugal force) of floating objects or gas bubbles would also be √2 of gravity alone. So they wouldn't submerge less or float faster upwards than normally.

Wonderful, thank you! So it would be correct to say that the magnitude of JUST the upward buoyancy force would remain the same with the centrifuge on or off? I'd also be very grateful for your credentials or basis of knowledge.
 
A.T. said:
Yes, but the apparent weight (gravity + centrifugal force) of floating objects or gas bubbles would also be √2 of gravity alone. So they wouldn't submerge less or float faster upwards than normally.
On the contrary. Buoyancy and apparent weight are both multiplied by a factor of ##\sqrt{2}## but inertial mass and viscosity are both unchanged. So falling rocks or rising gas bubbles would move faster than in ordinary one gee gravity.
 
Right said:
So it would be correct to say that the magnitude of JUST the upward buoyancy force would remain the same with the centrifuge on or off?
Yes, the vertical component stays the same.
 
jbriggs444 said:
On the contrary. Buoyancy and apparent weight are both multiplied by a factor of ##\sqrt{2}## but inertial mass and viscosity are both unchanged. So falling rocks or rising gas bubbles would move faster than in ordinary one gee gravity.
Yes, right. The difference of buoyancy and apparent weight also would scale by √2, while the resistance to movement and acceleration wouldn't. So they would move faster up/down. But they would not submerge more when floating on the surface.
 
  • Like
Likes   Reactions: jbriggs444
Off the cuff, I would suggest that bubbles would follow a curved path, tending to vertical at the centre, in addition to the rotation round the axis of spin. A more or less constant upward force and an 'inwards' force proportional to 1/radius of rotation. Just solve the equation of motion. Go on Go on Go on, as Mrs Doyle would say.