Is a 15kg object capable of generating 147N upward force in water?

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The discussion centers on calculating buoyancy for a 15kg object aiming to generate a 147N upward force in water. The formula used is buoyancy force minus the weight of the object, represented as PVg - mg. The participants confirm that for an object to float, the buoyancy force must equal the weight, resulting in a net force of zero. The target buoyancy of 147N is deemed appropriate depending on the object's volume and density of water, with practical insights shared from experience in designing buoyant systems.

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malek340
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I believe that the way to calculate buoyancy is buoyancy force-weight of object= upward force, which is PVg-mg= upward force. If I'm wrong please tell me. I set a target of 147N(15kg) upward force for my project product. Is it that strong? Give me your thoughts.
 
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Maths looks right.

15kG is about the weight of two Bowling balls.
 
If your "P" is the mass density of water and V is the volume of water of that part of the object below water, then, yes, the bouyancy force is PVg. The total force would be that minus the weight, mg. When the object is "floating", the two must cancel so that the total force is 0, neither up nor down.

As for a target bouyancy of 147 N, what is your question about it? For an icecube that would be much to high. For an ocean liner, it would be much too low!
 
I've designed many many buoyant systems for seawater. If figure volume in cubic feet and multiply by 60 lbf per cubic foot. The water is a little heavier than that, but I like the margins in case my material absorbs a little water.
 

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