Is a 15kg object capable of generating 147N upward force in water?

[malek340]

I believe that the way to calculate buoyancy is buoyancy force-weight of object= upward force, which is PVg-mg= upward force. If I'm wrong please tell me. I set a target of 147N(15kg) upward force for my project product. Is it that strong? Give me your thoughts.

 

[CWatters]

Maths looks right.

15kG is about the weight of two Bowling balls.

 

[HallsofIvy]

If your "P" is the mass density of water and V is the volume of water of that part of the object below water, then, yes, the bouyancy force is PVg. The total force would be that minus the weight, mg. When the object is "floating", the two must cancel so that the total force is 0, neither up nor down.

As for a target bouyancy of 147 N, what is your question about it? For an icecube that would be much to high. For an ocean liner, it would be much too low!

 

[Pkruse]

I've designed many many buoyant systems for seawater. If figure volume in cubic feet and multiply by 60 lbf per cubic foot. The water is a little heavier than that, but I like the margins in case my material absorbs a little water.

 

[PJC01]

Your understanding of the equation for calculating buoyancy force is correct. However, it is important to note that the buoyancy force is equal to the weight of the displaced water, not the weight of the object itself. This means that the buoyancy force will vary depending on the density of the object and the density of the water it is submerged in.

As for your target of 147N upward force for your project product, it is difficult for me to determine if that is a strong force without knowing more about the object and its intended use. I would suggest conducting experiments or simulations to test the buoyancy of your project product in different types of water (e.g. freshwater vs. saltwater) and under different conditions (e.g. fully submerged vs. partially submerged). This will give you a better understanding of how your product will behave in different scenarios.