How Much Weight Can a 2.8 kg Air Mattress Support in Water Before Sinking?

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SUMMARY

The discussion focuses on calculating the maximum weight a 2.8 kg air mattress can support in water before sinking. The key equations involved include the density formula (Density = Mass / Volume) and the principles of buoyant force, specifically that the buoyant force equals the weight of the fluid displaced. Given the dimensions of the mattress (2.00 m long, 0.500 m wide, and 0.100 m thick) and the density of water (1000 kg/m³), the buoyant force can be determined, allowing for the calculation of the maximum supported mass.

PREREQUISITES
  • Understanding of basic physics concepts, particularly buoyancy
  • Familiarity with the density formula and its application
  • Knowledge of volume calculation for rectangular prisms
  • Ability to apply mathematical equations to real-world scenarios
NEXT STEPS
  • Calculate the volume of the air mattress using its dimensions
  • Determine the buoyant force using the weight of the fluid displaced
  • Explore the relationship between weight and buoyant force in floating objects
  • Investigate real-world applications of buoyancy in various materials
USEFUL FOR

Students studying physics, educators teaching buoyancy concepts, and anyone interested in practical applications of fluid mechanics.

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Homework Statement



A 2.8 kg rectangular air mattress is 2.00 m long, 0.500 m wide, and 0.100 m thick. What mass can it support in water before sinking?


Homework Equations



Density = Mass / Volume
Magnitude of buoyant force = Weight of fluid displaced
Buoyant force = weight of floating object
Weight of object x Buoyant force = Density of object / Density of fluid
Density of water = 1000 kg/m3

The Attempt at a Solution



I can't figure out what I would need to do in order to answer the question or what I would need to find.
 
Physics news on Phys.org
Hello bor, you need to try a bit so that we can help :smile:
 

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