But we can't show that x = 2 is the only solution.

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Homework Help Overview

The discussion revolves around the equation 2^x + 3^x = 13, specifically addressing the assertion that x = 2 is a solution and how to prove it. Participants are exploring the nature of the problem and the methods to demonstrate the validity of this solution.

Discussion Character

  • Conceptual clarification, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Some participants attempt to manipulate the equation using logarithms, while others question the validity of these steps. There is also a discussion about substituting values directly into the equation to verify solutions.

Discussion Status

The conversation is ongoing, with various interpretations of the problem being explored. Some participants have provided guidance on how to approach proving the solution, while others express confusion about the requirements of the problem.

Contextual Notes

Participants are grappling with the distinction between solving the equation and proving a specific solution. There is mention of approximation methods and the implications of the phrasing used in the problem statement.

Champdx
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Homework Statement


2^x+3^x=13, x=2. How do i prove it?

The Attempt at a Solution


i did this
x log 2 + x log 3 = log 13
x(log 2 + log 3)=log 13
x(0.301+0.477)= 1.11
0.778x=1.11
x=1.43
 
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? Why not just substitute "2" for "x"?

[itex]2^x+ 3^x= 2^2+ 3^2= 4+ 9= 13[/itex].

You are not asked so solve the equation!
 
Hi Champdx! :smile:

(try using the X2 tag just above the Reply box :wink:)
Champdx said:
x log 2 + x log 3 = log 13

Nooo :redface:

that's log (x2x3) :wink:
 
Actually i know that the answer x=2 but how am i suppose to prove it?
 
If the question says "solve 2x + 3x = 13", then there's no exact way of doing it, you'll have to use an approximation method (or guess).

If the question says "show that 2x + 3x = 13 has a solution x = 2", or "prove that 2x + 3x = 13 has a solution x = 2", then all you need to do is to show that 22 + 32 = 13. :smile:
 
Champdx said:

Homework Statement


2^x+3^x=13, x=2. How do i prove it?

The Attempt at a Solution


i did this
x log 2 + x log 3 = log 13
You can't get the equation above from the one you started with. log(A + B) [itex]\neq[/itex] logA + logB. What you did was to take the log of both sides to get
log(2^x + 3^x) = log 13. That's a legitimate step, but it doesn't lead you anywhere.
The problem is that log(2^x + 3^x) [itex]\neq[/itex] log 2^x + log 3^x.
Champdx said:
x(log 2 + log 3)=log 13
x(0.301+0.477)= 1.11
0.778x=1.11
x=1.43
 
Is there any way to solve this question by calculation?

Thanks.
 
Nope. :redface:
 
tiny-tim said:
If the question says "solve 2x + 3x = 13", then there's no exact way of doing it, you'll have to use an approximation method (or guess).

If the question says "show that 2x + 3x = 13 has a solution x = 2", or "prove that 2x + 3x = 13 has a solution x = 2", then all you need to do is to show that 22 + 32 = 13. :smile:

Champ, read this quote again. There are only two options:
1) "Solve..." or
2) "Show that"/"Prove..."

There's a phrase that comes up frequently in math (that honestly kinda p*sses me off!)...
"By inspection...".
This means "I can SEE the answer, but I can't/won't show HOW you could get the same answer without guessing". There might be a better description out there for this phrase, which I think applies to our situation.

We can see that x = 2 is a solution. We can see that it is a UNIQUE solution because increasing/decreasing x will increase/decrease BOTH terms on the left hand side of the equation...
 

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