C 12B 2009 Problem 17: Finding the Fraction of Air in a Heated Souffle

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SUMMARY

The discussion focuses on solving a physics problem related to the fraction of air in a heated souffle. The initial temperature is 283.15 K, and it is heated to 463.65 K, resulting in a volume increase of 1.4 times. The ideal gas law (PV=nRT) is applied to determine the relationship between the air volume before and after heating, with the assumption that the pressure remains constant during the process. The key equation derived is 1=(Vair-f - Vair-o)/0.4, which helps in calculating the air volume fractions.

PREREQUISITES
  • Understanding of the Ideal Gas Law (PV=nRT)
  • Knowledge of thermal expansion concepts
  • Familiarity with volume fractions in mixtures
  • Basic algebra for manipulating equations
NEXT STEPS
  • Study the Ideal Gas Law applications in real-world scenarios
  • Learn about thermal expansion coefficients of different materials
  • Explore the concept of volume fractions in mixtures and their calculations
  • Investigate the effects of pressure on gas behavior during heating
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Students in physics or chemistry courses, educators teaching thermodynamics, and anyone interested in the principles of gas behavior and thermal expansion in culinary applications.

skate_nerd
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Homework Statement



Okay so I'm trying to figure out how to get this answer. there's a souffle made of some ingredients and filled with these ingredients along with some air. Everything starts off at 283.15 K and gets heated in the oven to 463.65 K. Also assume that the air expands with heat as an ideal gas, and the other ingredients' expansion is negligible. Also the volume after heating up is 1.4 times the volume before heating up.

What we are looking to find is the fraction of the volume of the souffle that is air before being heated up, and the fraction of the volume of the souffle that is air after being heated.

Homework Equations



PV=T
PV=nRT

Vtotal=Vair+Vother
therefore
Vtotal-o=Vair-o+Vother
Vtotal-f=Vair-f+Vother
also
Vother-o=Vother-f
Vtotal-f=1.4Vtotal-o

The Attempt at a Solution



So I've messed around with these known equations and legitimately came up with something that I feel is in the right direction of solving the problem. I found that
1=(Vair-f - Vair-o)/0.4. I figure now that I can use PV=T to get this formula in terms of one variable of the air's volume, however I am not really sure how to do that since I have no value for P. I'm assuming also in this problem that being a souffle, when it heats up the top just tightens to keep the pressure constant.

So that's all I got. If somebody could help or point me in the right direction for solving this that would be awesome.
 
Last edited:
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Is the pressure constant during the heating?

ehild
 
skate_nerd said:
So I've messed around with these known equations and legitimately came up with something that I feel is in the right direction of solving the problem. I found that
1=(Vair-f - Vair-o)/0.4. I figure now that I can use PV=T to get this formula in terms of one variable of the air's volume, however I am not really sure how to do that since I have no value for P. I'm assuming also in this problem that being a souffle, when it heats up the top just tightens to keep the pressure constant.

So that's all I got. If somebody could help or point me in the right direction for solving this that would be awesome.
Answer ehild's question and assume that the quantity of air (n) does not change. By what factor does a given volume of air increase in going from 283.15K to 463.65K? Call that x. You can then write out an equation for the volume of the souffle after expansion in terms of the original volumes of air and the original volume of other ingredients.

AM
 

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