Calc Angle of Incidence & Reflection to Solve Determining Angle Homework

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SUMMARY

The discussion focuses on calculating the angle of incidence and reflection for a solid body colliding with a sphere of radius one and height z. The correct approach involves breaking down the velocity vector into tangential and central components, reversing the central component's direction, and combining both to determine the bounce-off velocity vector. The angle between the incident and reflected angles is halved to find the desired angle. The formula to calculate this angle is ##\pi - 2 \arctan {z\over R}##, applicable under the assumption of a fixed sphere and elastic collision.

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Homework Statement



Suppose a solid body approaches a sphere of radius one and height z, how do I calculate the angle ##\theta## at which the body bounces off the sphere? An image is attached:

blah-jpg.78628.jpg


Homework Equations



Angle of incidence, reflection and velocity

The Attempt at a Solution



I was told that the following but I still do not know how to apply it correct.

"Break down the velocity vector of the solid body into two components: one is tangential to the sphere, another one points to the centre of the sphere. Reverse the direction of the central component and add the two component together and you will have the bounce off velocity vector. The angle between incident and reflected angle is what you need. Divide it by two and you will have the answer."
 
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What you were told in this thread applies if the sphere has a fixed position (i.e. is solidly welded onto whatever) and the collision is fully elastic. The one who gave you that advice forgot to mention those restrictions. I don't see any difference with the question in the current thread, so now we have a duplication, which is frowned upon as undesirable in PF.

As long as the solid body mass is much smaller than the sphere mass, both are pretty hard and neither spin nor friction play a role, it is at best a reasonable approximation.

If your application doesn't require more sophistication, then you're fine.

As to your question: there is a z in your drawing. Would that be the height above the sphere center ? Then calculate ##\pi - 2 \arctan {z\over R}##.
 
BvU said:
What you were told in this thread applies if the sphere has a fixed position (i.e. is solidly welded onto whatever) and the collision is fully elastic. The one who gave you that advice forgot to mention those restrictions. I don't see any difference with the question in the current thread, so now we have a duplication, which is frowned upon as undesirable in PF.

I am sorry, I will not do that again.
As to your question: there is a z in your drawing. Would that be the height above the sphere center ? Then calculate ##\pi - 2 \arctan {z\over R}##.

Thank you very much!
 

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