Calc II integral with quadratic in numerator

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    Integral Quadratic
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SUMMARY

The discussion centers on finding the antiderivative of the function 1/(3x² + 2). A participant suggests factoring out a 3 from the denominator and applying a trigonometric substitution involving tangent. The transformation leads to the expression 1/3 * 1/(x² + 2/3), which simplifies the integration process. This method provides a clear pathway to solving the integral effectively.

PREREQUISITES
  • Understanding of antiderivatives and integration techniques
  • Familiarity with trigonometric substitutions in calculus
  • Knowledge of factoring polynomials
  • Basic algebraic manipulation skills
NEXT STEPS
  • Study trigonometric substitution methods in calculus
  • Practice integrating rational functions with quadratic denominators
  • Learn about the properties of definite and indefinite integrals
  • Explore advanced integration techniques, such as partial fraction decomposition
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Students and educators in calculus, mathematicians focusing on integration techniques, and anyone seeking to enhance their skills in solving complex integrals involving quadratics.

10martineze
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Hi everyone! I need to find the antiderivative(1/(3x^2 + 2)) but am not sure which approach to take. I have tried the following only to arrive at a dead end.

1/3x2+2= .5(1/(3(x/sqrt(2))2+1)= (1/6)(1/((x/sqrt(6))2+(1/3))

Thank you so much!
 
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10martineze said:
Hi everyone! I need to find the antiderivative(1/(3x^2 + 2)) but am not sure which approach to take. I have tried the following only to arrive at a dead end.

1/3x2+2= .5(1/(3(x/sqrt(2))2+1)= (1/6)(1/((x/sqrt(6))2+(1/3))

Thank you so much!
Factor a 3 out of the denominator, and then use a trig substitution, which will involve a tangent.
[tex]\frac{1}{3x^2 + 2} = \frac{1}{3}\frac{1}{x^2 + 2/3}[/tex]
 

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