Calc III: Shortest Distance in 3D Problem

Click For Summary
SUMMARY

The discussion focuses on finding the shortest distance from the point P = (0, 1, 2) to the line defined by l(t) = (1+t, 2-2t, 3+3t) using the distance formula in Calculus III. The correct approach involves substituting the line's parametric equations into the distance formula, simplifying, and then differentiating to find the critical points. The participant initially misapplied the formula but later corrected their approach, indicating the importance of verifying calculations in multivariable calculus.

PREREQUISITES
  • Understanding of Calculus III concepts, specifically distance in three dimensions.
  • Familiarity with parametric equations and their derivatives.
  • Proficiency in using the distance formula in three-dimensional space.
  • Ability to perform algebraic simplifications and solve equations.
NEXT STEPS
  • Study the derivation and application of the distance formula in three dimensions.
  • Learn about critical points and their significance in optimization problems.
  • Explore the concept of parametric equations in greater depth.
  • Practice solving similar problems involving distances from points to lines in 3D space.
USEFUL FOR

Students and educators in calculus, particularly those focusing on multivariable calculus, as well as anyone seeking to improve their problem-solving skills in three-dimensional geometry.

nchin
Messages
172
Reaction score
0
Calculus III, find shortest distance, 3 dimension problem? check my answer please??

What is the shortest distance from the point P = (0, 1, 2) to the line given by l(t) = (1+t, 2-2t, 3+3t)?

use distance formula

d = sqrt ((x-0)^(2) + (y-1)^(2) + (z-2)^(2))

d^(2) = ((x)^(2) + (y-1)^(2) + (z-2)^(2))

substitute l(t) values

=((1+t)^(2) + (1-2t)^(2) + (1+3t)^(2))

simplify

l ' (t) = 2 + 2t + 8t - 4 +6 + 18t

= 2 + 2t + 8t - 4 + 6 + 18t

=28t + 4

4(1+7t) = 0

t = - 1/7What do i do after i find the t value?
 
Last edited:
Physics news on Phys.org


nchin said:
What is the shortest distance from the point P = (0, 1, 2) to the line given by l(t) = (1+t, 2-2t, 3+3t)?

use distance formula

d = sqrt ((x-0)^(2) + (y-1)^(2) + (z-2)^(2))

d^(2) = ((x)^(2) + (y-1)^(2) + (z-2)^(2))

substitute l(t) values

=((1+t)^(2) + (1-2t)^(2) + (1+3t)^(2))

simplify

l ' (t) = 2 + 2t + 8t - 4 +6 + 18t

= 2 + 2t + 8t - 4 + 6 + 18t

=28t + 4

4(1+7t) = 0

t = - 1/7


What do i do after i find the t value?

I didn't check your work, but the t value will tell you what point on the line is closest. Then what?
 


LCKurtz said:
I didn't check your work, but the t value will tell you what point on the line is closest. Then what?

nvm my whole answer is wrong. i used the wrong formula. i figured it out thanks.
 

Similar threads

  • · Replies 2 ·
Replies
2
Views
1K
Replies
2
Views
1K
Replies
13
Views
2K
  • · Replies 2 ·
Replies
2
Views
1K
Replies
12
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 12 ·
Replies
12
Views
3K
  • · Replies 14 ·
Replies
14
Views
3K
  • · Replies 2 ·
Replies
2
Views
2K
Replies
1
Views
2K