Calc Lattice Constant of Solid Manganese

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I am told solid manganese exists in a simple cubic structure. If its Ar is 54.94 and its density is 7440 Kg m^-3, How do I calculate the lattice constant for this material?
 
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Hi adambinch, welcome to PF. You need to find out how many atoms there are in the simple cubic unit cell. Then you can set up a calculation like

\left(\frac{\mathrm{atoms}}{\mathrm{cell}}\right)\left(\frac{\mathrm{weight}}{\mathrm{mole}}\right)\left(\frac{\mathrm{mole}}{\mathrm{atoms}}\right)\left(\frac{\mathrm{volume}}{\mathrm{weight}}\right)=\left(\frac{\mathrm{volume}}{\mathrm{cell}}\right)

and the volume per unit cell should lead you to the lattice parameter. Does this help?
 
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