Calc stationary points question

[meee]

c and d are positive integers greater than one

y = (c*e^d) / (x^d +1)

I need to try and find the co-ordinates for stationary point. apparently the general co-ordinates for the SP are not possible to find and i must explain why?

help aprectiatedohh where i am up to... i think i got x^(d-1) = 0
wat u guys get?

 

[meee]

anybody?

 

[Curious3141]

c and d are positive integers greater than one

y = (c*e^d) / (x^d +1)

I need to try and find the co-ordinates for stationary point. apparently the general co-ordinates for the SP are not possible to find and i must explain why?

help aprectiated


ohh where i am up to... i think i got x^(d-1) = 0
wat u guys get?

What do you get when you differentiate the expression? Do you know chain rule?

 

[meee]

i used quotient rule

[ (x^d +1)(0) - (ce^d)(dx^(d-1)) ] / [ (x^d +1)^2 ]

= -ce^ddx^(d-1)) / (x^d +1)^2

 

[J77]

That's correct

I can only see x=0 for the constraints you give which gives y as...

 

[HallsofIvy]

At a stationary point, either the derivative is 0 or the derivative does not exist. A fraction is 0 only if the numerator is 0 and "does not exist" only if the denominator is 0. What does that tell you about stationary points for this function? What about the value of the function at that value of x?

 

[meee]

thanks j77 :)

HMMm hallsoivy nice thinking, i like it
stationary points of this function...
derivative is 0 when -c(e^d)dx^(d-1) = 0...
-c(e^d)d cannot = 0,
so x^(d-1) = 0...and then?

What about the value of the function at that value of x?
wats this?